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3 years ago

Which ratio is the same as 2/3

Mathematics

2 answers:

kap26 [50]3 years ago

6 0

Answer:

4/6

Step-by-step explanation:

swat323 years ago

4 0

4/6 is the same as 2/3

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The numbers 1-11 are placed in a bag. What is the probability of drawing a even number? PLEASE HELP ASAP

Lady_Fox [76]

Answer:

5/11

Step-by-step explanation:

Between numbers 1 - 11, the evens are 2, 4, 6, 8, and 10. Therefore, there are 5 evens.

Out of the eleven choices in the bag, there are 5 possible choices to be picked out of the 11 total choices.

Therefore, the probability of drawing an even number over the number of choices is 5/11.

6 0

3 years ago

If f(x)=1/x+2 what is f(3+h)

Leviafan [203]

Let x = 3+h
$\frac{1}{(3 + h) + 2} \\ = \frac{1}{h + 3 + 2} \\ = \frac{1}{h + 5}$
The answer is A.

6 0

4 years ago

Read 2 more answers

Which of the following statements correctly uses the distributive property?

Anna007 [38]

Answer:

d) 9(-7+6) = 9(-7) + 9(6) is the correct use of Distributive Property.

Step-by-step explanation:

Distributive Property states that form any three expressions A, B and C

1. A( B -C) = AB - AC

2. A (B + C ) = AB + AC

Now, here

a) 0-3(12+5)= -3(12) - (-3)(5)

Solving Left side by distributive property, we get

0-3(12+5) = -3(12) + (-3)(5)

and -3(12) + (-3)(5) ≠ Right Side -3(12) - (-3)(5)

⇒NO CORRECT USE OF DISTRIBUTIVE PROPERTY

b) 7(19 - 8) = 7(19) - 8

Solving Left side by distributive property, we get

7(19 - 8) = 7(19) - 7(8)

and 7(19) - 7(8) ≠ Right Side 7(19) - 8

⇒NO CORRECT USE OF DISTRIBUTIVE PROPERTY

c) -2(15 - 3) = -2(15) + (-2)(3)

Solving Left side by distributive property, we get

-2(15 - 3) = -2(15) - (-2)(3)

and -2(15) - (-2)(3) ≠ Right Side -2(15) + (-2)(3)

⇒NO CORRECT USE OF DISTRIBUTIVE PROPERTY

d) 9(-7+6) = 9(-7) + 9(6)

Solving Left side by distributive property, we get

9(-7+6) = 9(-7) + 9(6)

and 9(-7) + 9(6) = Right Side 9(-7) + 9(6)

⇒ CORRECT USE OF DISTRIBUTIVE PROPERTY

3 0

3 years ago

Assume that we have m coins. We toss each one of them n times. The probability of heads showing up for each coin isp. What’s the

olga nikolaevna [1]

Answer:

$1-(1-p^n)^m$

Step-by-step explanation:

For a coin, the probability of head showing in a single toss is $p$ .

$P(H)=p$

Its complement, the probability of not head is

$P(\Sim H)=1-p$

This is a binomial distribution. In $n$ tosses, the probability of having all heads (i.e. $n$ heads) is

$P(\text{all heads})=\binom{n}{n}p^n(1-p)^0=p^n$

Let's call this value $a$ .

For $m$ coins, we determine the probability of at least 1 coin showing all heads by first finding its complement i.e. the probability of no coin showing all heads. This is also a binomial distribution.

$P(\text{no coin showing all heads})=\binom{m}{0}a^0(1-a)^m=(1-a)^m$

$P(\text{at least 1 coin showing all heads})=1-P(\text{no coin showing all heads})$

$P(\text{no coin showing all heads})=1-(1-a)^m=1-(1-p^n)^m$

8 0

3 years ago

Nico and Lorena used different methods to determine the product of three fractions.

umka21 [38]

Answer:

Nico's solution is correct

Step-by-step explanation:

Lorena introduced a spurious minus sign in the denominator in the next-to-last step, so ended up with a result that has the wrong sign.

4 0

3 years ago

Read 2 more answers