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Makovka662 [10]
3 years ago
5

Please help me i need answers ASAP!!

Mathematics
1 answer:
mafiozo [28]3 years ago
4 0

Answer:

I believe the first one is A

Step-by-step explanation:

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Question in screenshot
sesenic [268]

Answer:

10

Step-by-step explanation:

use pythagorean theorm

√(8^2+6^2) = 10

6 0
3 years ago
A vertical number line is given.
Ad libitum [116K]

The absolute value of the number plotted on the number line is; 0.5

<h3>How to find Absolute Value?</h3>

The absolute value (or modulus) | x | of a real number x is the non-negative value of x without regard to its sign. For example, the absolute value of 5 is 5, and the absolute value of −5 is also 5. The absolute value of a number may be thought of as its distance from zero along real number line

Thus, if 0.5 is marked on the number line, from the given options, we can say that if we apply the definition above that |0.5| = 0.5

Read more about Absolute Value at; brainly.com/question/24368848

#SPJ1

4 0
2 years ago
Read 2 more answers
Evaluate the expression (2x + y) - z when x= 3, y = 4, z =5​
Lapatulllka [165]

Answer:

5

Step-by-step explanation:

(2x + y) - z

Let x=3  y=4 and z=5

2*3 +4 -5

Multiply and divide first

6 +4 -5

Then add and subtract

10-5

5

5 0
3 years ago
And he needs at least 1000 GB of storage to take pictures and videos on her upcoming vacation she checks and find she has 105 cu
stellarik [79]

Answer:

the answer is I do not know 25

3 0
3 years ago
Read 2 more answers
Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.
valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with f^{-1}(x)

Given that:

I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = a^{-1}(x) = a(x)  Hence, I is true.

II. y =\dfrac{1}{x}

Replacing y with and x with y:

x =\dfrac{1}{y}

x=\dfrac{1}{a^{-1}(x)}

\Rightarrow a^{-1}(x) = \dfrac{1}{x}

a^{-1}(x) = a(x)  Hence, II is true.

III. y =x^{2}

Replacing y with and x with y:

x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)

 Hence, III is not true.

IV. y =x^{3}

Replacing y with and x with y:

x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0
3 years ago
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