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2 years ago

Graph each quadrilateral ABCD. Then determine the most precise name for it.

Mathematics

1 answer:

azamat2 years ago

3 0

This quadrilateral is 'deltoid'. All the details are in the picture.

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Exercise 1: In the right triangle below, calculate the measurement of the unknown side. Show your work.

vekshin1

Answer:

Exercise 1:

base [b]=8cm

perpendicular [p]=6cm

hypotenuse [h]=?

By using Pythagoras law

h²=p²+b²

h²=6²+8²

h=√100

h=10cm

So another side's length is 10cm

Exercise 2:

base [b]=6m

perpendicular [p]=bm

hypotenuse [h]=8m

By using Pythagoras law

h²=p²+b²

8²=b²+6²

b²=8²-6²

b=√28=2√7 0r 5.29 or 5.3

So height of kite is√28or 2√7 0r 5.29 or 5.3 m

Step-by-step explanation:

[Note: thanks for translating]

4 0

2 years ago

Solve -7x^2+x+9=-6x quadratic formula

myrzilka [38]

Answer:

$-7x^2+x+9=-6x$

$-7x^2+x+9+6x=-6x+6x$

$-7x^2+7x+9=0$

$quadratic\: formula$

$x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\left(-7\right)\cdot \:9}}{2\left(-7\right)}$

$\sqrt{-7^{2} -4(-7)\times9} =\sqrt{301}$

$x_{1,\:2}=\frac{-7\pm \sqrt{301}}{2\left(-7\right)}$

$\frac{-7+\sqrt{301}}{2\left(-7\right)}$

$=\frac{-7+\sqrt{301}}{-2\cdot \:7}$

$=\frac{-7+\sqrt{301}}{-14}$

$\frac{-7-\sqrt{301}}{2\left(-7\right)}$

$=\frac{-7-\sqrt{301}}{-2\cdot \:7}$

$=\frac{-7-\sqrt{301}}{-14}$

$answer=\frac{7+\sqrt{301}}{14}$

$OAmalOHopeO$

7 0

2 years ago

A shopkeeper sold a watch for Rs 810 at 10% loss. How much did he pay to buy the watch ?

Svetlanka [38]

Answer:

Rupees 891

Step-by-step explanation:

If you multiply 810 times 0.1 which is the decimal of 10%, you get 81 which you can add to 810 to get 891 which is the price the shopkeeper payed to buy the watch.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

7 0

2 years ago

To determine the number of square centimeters in 8 square inches, multiply 8 by 6.45. true false

liraira [26]

The answer would be true

8 0

2 years ago

Read 2 more answers

Can someone help me?

juin [17]

Answer:

5/12

Step-by-step explanation:

8 0

2 years ago