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3 years ago

Write a word problem where something Starts at 8:25 AM p.m. and ends at 1:43 PM

Mathematics

2 answers:

Semmy [17]3 years ago

5 0

TJ plays Xbox from 8:25 am to 1:43 pm

kobusy [5.1K]3 years ago

3 0

In this question , we have to create a word problem using the times 8:25 AM and 1:43 PM .

And the problem is :

Suppose I started painting my house at 8:25 AM and completed the painting work by 1:43 PM. How many minutes I took in painting the house .

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Place the following values in order from least to greatest: 3/4, 0.7, 4/5, 65.5%, 0.72

Tema [17]

Answer:

4/5, 3/4, 0.72, 0.70, %65.5

Step-by-step explanation:

65.5/100=0.655

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3 years ago

Point A (4,-3) is reflected over the y- axis. What are<br> the coordinates of A'?

yan [13]

Answer:

A'(-4,-3)

Step-by-step explanation:

use formula of reflection over y axis

(x,y)=(-x,y)

A(4,-3)=A'(-4,-3)

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3 years ago

Read 2 more answers

the scatter plot shows the relationship between the cost of animal feed and its weight. which option best describes the associat

Ludmilka [50]

Answer: As the weight increases, the price increases

Step-by-step explanation: it’s the only one that actually makes sense

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3 years ago

The image represents what geometric construction? A) Copy a triangle construction B) Copy a segment construction C) Parallel lin

Umnica [9.8K]

Answer:

d perpendicular bisected and midpoint

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3 years ago

Point B has coordinates (1,2). The x-coordinate of point A is -8. The distance between point A and point B is 15 units. What

Xelga [282]

Answer:

The possible coordinates of point A are $A_{1} (x,y) = (-8, 14)$ and $A_{2} (x,y) = (-8, -10)$ , respectively.

Step-by-step explanation:

From Analytical Geometry, we have the Equation of the Distance of a Line Segment between two points:

$l_{AB} = \sqrt{(x_{B}-x_{A})^{2} + (y_{B}-y_{A})^{2}}$ (1)

Where:

$l_{AB}$ - Length of the line segment AB.

$x_{A}, x_{B}$ - x-coordinates of points A and B.

$y_{A}, y_{B}$ - y-coordinates of points A and B.

If we know that $l_{AB} = 15$ , $x_{A} = -8$ , $x_{B} = 1$ and $y_{B} = 2$ , then the possible coordinates of point A is:

$\sqrt{(1+8)^{2}+(2-y_{A})^{2}} = 15$

$81 + (2-y_{A})^{2} = 225$

$(2-y_{A})^{2} = 144$

$2-y_{A} = \pm 12$

There are two possible solutions:

1) $2-y_{A} = -12$

$y_{A} = 14$

2) $2 - y_{A} = 12$

$y_{A} = -10$

The possible coordinates of point A are $A_{1} (x,y) = (-8, 14)$ and $A_{2} (x,y) = (-8, -10)$ , respectively.

8 0

3 years ago