Question

What is the equation,in point slope form,for a line that goes through (8,-4) and has a slope of -5/6

Answer 1

The point-slope formula:

$y-y_1=m(x-x_1)$

We have

$(8,\ -4)\to x_1=8,\ y_1=-4\\\\m=-\dfrac{5}{6}[/tx]Substitute:[tex]y-(-4)=-\dfrac{5}{6}(x-8)\\\\y+4=-\dfrac{5}{6}(x-8)$