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4 years ago

What is the area of a triangle that has a base of 15 yards and a height of 11 yards?

Mathematics

1 answer:

erma4kov [3.2K]4 years ago

4 0

Answer:

82.5

Step-by-step explanation:

The formula for the area of triangle is 1/2 B * H

1/2 of the base is 7.5

multiply that by 11

and you get

82.5

You might be interested in

A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of

GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 1.989.

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

$M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23$

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0

3 years ago

Show ALL your work. @100 POINTS + BRAINLYEST + 5 STARS AND LIKE Find MG. ∆EGF~∆EML.

Afina-wow [57]

Answer:

MG = 56

Step-by-step explanation:

The triangles EML and EGF are similar thus the ratios of corresponding sides are equal, that is

$\frac{EM}{EG}$ = $\frac{EL}{EF}$ , and substituting values

$\frac{16}{5x+2}$ = $\frac{28}{126}$ ( cross- multiply )

28(5x + 2) = 2016 ( divide both sides by 28 )

5x + 2 = 72 ( subtract 2 from both sides )

5x = 70 ( divide both sides by 5 )

x = 14

Thus

EG = 5x + 2 = 5(14) + 2 = 70 + 2 = 72

Hence

MG = EG - EM = 72 - 16 = 56

4 0

3 years ago

What is the result when 6 x^4 + 14 x^3 − 9 x^2 + 4 x + 1 +4x+1 is divided by 3 x 2 + x + 1

Artist 52 [7]

16.65 that is the answer i guess

7 0

4 years ago

Read 2 more answers

Find the absolute maximum and absolute minimum values of f on the given interval.

anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

$f(x)=xe^{-\frac{x^{2}}{32} }$ , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

Absolute maximum is a point where the function has its greatest possible value.

Absolute minimum is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

$f(x)=xe^{-\frac{x^{2}}{32} }$

Using the product rule, first derivative will be:

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$ = 0

$1-\frac{x^{2}}{16}=0$

$\frac{x^{2}}{16}=1$

$x^{2}=16$

x = ±4

x can't be -4 because it is not in the interval [-2,8].

$f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76$

$f(4)=4e^{-\frac{4^{2}}{32} }=2.42$

$f(8)=8e^{-\frac{8^{2}}{32} }=1.08$

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0

3 years ago

An investment of P=1237.50 is compounded annually with a 6.75% APR . Find the value of the investment after 5 and a half years.

Ber [7]

Answer:

Under compound interest, not only does the principal generate interest, so does the previous accumulated interest. The future value F of P dollars compounded annually for t years with an annual percentage rate (APR) r expressed as a decimal is .

5 0

3 years ago

Read 2 more answers