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pentagon [3]
3 years ago
6

What is the area of a triangle that has a base of 15 yards and a height of 11 yards?

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
4 0

Answer:

82.5

Step-by-step explanation:

The formula for the area of triangle is 1/2 B * H

1/2 of the base is 7.5

multiply that by 11

and you get

82.5

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What is a skewed to the right histogram
Zinaida [17]

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A "skewed right" distribution is one in which the tail is on the right side. A "skewed left" distribution is one in which the tail is on the left side. The above histogram is for a distribution that is skewed right. ... Be that as it may, several "typical value" metrics are often used for skewed distributions.

Discussion of Skewness: The above is a histogram of the SUNSPOT.DAT data set. A ...

Some Causes for Skewed Data: Skewed data often occur due to lower or upper

8 0
3 years ago
If you flip a coin 4 times, what is the probability that you will get exactly 2 tails?
ioda

Answer:

0.375

Step-by-step explanation:

5 0
3 years ago
Order from greatest to least:show your work❗️<br><br> 12,-4,8,-3,0
Aneli [31]
The answer would be 12, 8, 0, -3, -4.

The answer is that because 12 is a positive number so that's higher than negative, 8 goes second because its positive and higher than the others, 0 is third because negatives numbers are LOWER than 0, not higher, -3 is next because higher negative numbers are always lower, not greater than smaller numbers because -8 is LOWER than -4 since its on the left of a number line.
6 0
3 years ago
Use the triangle below to find cos V.
Semenov [28]

Answer:

cos\ V = \frac{2\sqrt{29}}{29}

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

cos\theta = \frac{Adjacent}{Hypotenuse}

In this case:

cos V= \frac{TV}{UV}

Where

TV = 6

and

UV^2 = TV^2 + TU^2 -- Pythagoras

UV^2 = 6^2 + 15^2

UV^2 = 261

Take square roots

UV = \sqrt{261

UV = \sqrt{9*29

UV = \sqrt{9} *\sqrt{29

UV = 3\sqrt{29

So:

cos V= \frac{TV}{UV}

cos\ V = \frac{6}{3\sqrt{29}}

cos\ V = \frac{2}{\sqrt{29}}

Rationalize:

cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}

cos\ V = \frac{2\sqrt{29}}{29}

8 0
2 years ago
Find the equation of the line that passes through point A (1,7) and B (-3, -1)
amid [387]

Answer:

The equation of the line is 2 x - y + 5 = 0.

Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( x_{1}, y_{1} ) & ( x_{2}, y_{2} )-

 y - y_{1}  = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }   ( x - x_{1}  )

i.e. <em> y - 7= \frac{- 1 - 7}{ -3-1}  ( x- 1)</em>

<em>       y - 7 =  \frac{- 8}{- 4} ( x -1)</em>

<em>       y - 7 =  2 ( x - 1) </em>

<em>       y - 7  =   2  x - 2</em>

<em>       2 x - y + 5 = 0</em>

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1)  is 2 x - y  + 5 = 0.

6 0
3 years ago
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