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givi [52]
4 years ago
9

Russel was scheduled to leave on his vacation when major snowstorm cane through and canceled three-fourths of the flights out of

the airport. There were 496 flights scheduled for that day. How many flights were able to leave the airport?
Mathematics
1 answer:
ludmilkaskok [199]4 years ago
7 0

Answer:

<u>124 flights</u> will leave the airport.

Step-by-step explanation:

Let the number of flights that will leave be 'x'.

Given:

Total number of flights (N) = 496

Flights that got cancelled (C) = Three-fourths of total flights

Now, number of flights that got cancelled is given as:

C=\frac{3}{4}\times 496\\\\C=\frac{1488}{4}\\\\C=372

Now, total flights = Total flights cancelled + Total flights that will leave

Framing in equation form, we get:

N=C+x

Plug in the given values and solve for 'x'. This gives,

496=372+x\\\\x=496-372\\\\x=124

Therefore, 124 flights will leave the airport.

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\text{if }x>7\text{, then }|x|>7 is a valid argument

|y|>7\text{, so }y=7 is not a valid argument

For the first argument: \text{if }x>7\text{, then }|x|>7

From the definition of absolute value function

|x|=x   if x\ge0

That is every positive number is its own absolute value. Since

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For the second argument: |y|>7\text{, so }y=7

From the definition of absolute value function

|y|:=\left \{ {y\text{  if }y\ge0}\atop{-y\text{  if }y

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|y|>7:=\left \{ {y>7\text{  if }y\ge0}\atop{-y>7\text{  if }y

or

|y|>7:=\left \{ {y>7\text{  if }y\ge0}\atop{y

no part of the definition allow for the option y=7. So the second argument is not valid.

Learn more here: brainly.com/question/11897796

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