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Irina18 [472]
3 years ago
5

If x>7, then |x|>7. |y|>7, so y=7 Valid or invalid?

Mathematics
1 answer:
Alex3 years ago
7 0

\text{if }x>7\text{, then }|x|>7 is a valid argument

|y|>7\text{, so }y=7 is not a valid argument

For the first argument: \text{if }x>7\text{, then }|x|>7

From the definition of absolute value function

|x|=x   if x\ge0

That is every positive number is its own absolute value. Since

x>7\implies x\ge0,

we can argue that

x>7\implies |x|>7

so the first argument is valid

For the second argument: |y|>7\text{, so }y=7

From the definition of absolute value function

|y|:=\left \{ {y\text{  if }y\ge0}\atop{-y\text{  if }y

This means that

|y|>7:=\left \{ {y>7\text{  if }y\ge0}\atop{-y>7\text{  if }y

or

|y|>7:=\left \{ {y>7\text{  if }y\ge0}\atop{y

no part of the definition allow for the option y=7. So the second argument is not valid.

Learn more here: brainly.com/question/11897796

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<h3>Answer: Choice D</h3>

Domain: {-3, -1, 2, 4, 6}  

Range: {-2, 1, 2, 4, 6}

===========================================

Explanation:

The domain is the set of possible x values of a relation or function. To form the domain, we just list out the x coordinates of each point

Point A is located at (-3, 4) so the x coordinate x = -3 is part of the domain

Point B is at (-1,1) meaning x = -1 is also part of the domain

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--------------------

The range is a similar story, but we look at the y coordinates now. Point A has y coordinate 4, so y = 4 is part of the range.

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With any set, the order does not matter. Though convention is to list the items from smallest to largest.

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