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Irina18 [472]
3 years ago
5

If x>7, then |x|>7. |y|>7, so y=7 Valid or invalid?

Mathematics
1 answer:
Alex3 years ago
7 0

\text{if }x>7\text{, then }|x|>7 is a valid argument

|y|>7\text{, so }y=7 is not a valid argument

For the first argument: \text{if }x>7\text{, then }|x|>7

From the definition of absolute value function

|x|=x   if x\ge0

That is every positive number is its own absolute value. Since

x>7\implies x\ge0,

we can argue that

x>7\implies |x|>7

so the first argument is valid

For the second argument: |y|>7\text{, so }y=7

From the definition of absolute value function

|y|:=\left \{ {y\text{  if }y\ge0}\atop{-y\text{  if }y

This means that

|y|>7:=\left \{ {y>7\text{  if }y\ge0}\atop{-y>7\text{  if }y

or

|y|>7:=\left \{ {y>7\text{  if }y\ge0}\atop{y

no part of the definition allow for the option y=7. So the second argument is not valid.

Learn more here: brainly.com/question/11897796

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liberstina [14]

The cosine function with the given characteristics is:

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<h3>How to get the cosine function?</h3>

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Where A is the amplitude and p is the phase, then we know that:

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3 0
2 years ago
1. 7/8 + 1 1/2 =<br> 2. 268.97 + 38.659 =<br> 3. 2 3/4 - 2/3 =<br> 4. 870.45- 96.38=
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Given y=5x−3 with the domain D: {−2, −1, 0, 1, 2}, fill in the missing values of the table below.
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Answer:

see below

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7 0
2 years ago
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