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PilotLPTM [1.2K]
3 years ago
10

5^3x=25 x= type and integer or a simplified fraction

Mathematics
1 answer:
kifflom [539]3 years ago
8 0
125x = 25
x = 0,2
There you go :)
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the first answer

Step-by-step explanation:

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Prove, cotx -tanx= 2 cot2x
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Step-by-step explanation:

<em>cotx-</em><em> </em><em>tanx</em><em>=</em><em> </em><em>2cot2x</em>

<em>L.H.S</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>cosx</em><em>/</em><em>sinx-</em><em> </em><em>sinx</em><em>/</em><em>cosx</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>cos</em><em>²</em><em>x-</em><em> </em><em>sin</em><em>²</em><em>x</em><em>)</em><em>/</em><em> </em><em>sinxcosx</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>[</em><em> </em><em>cos</em><em>²</em><em>x-</em><em>(</em><em>1</em><em>-cos</em><em>²</em><em>x</em><em>)</em><em>]</em><em>/</em><em>sinxcosx</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em> </em><em>2cos</em><em>²</em><em>x-1</em><em>)</em><em>/</em><em>sinxcosx</em>

<em> </em><em> </em><em> </em><em>2cosx</em><em>/</em><em> </em><em>2sinxcosx</em>

<em> </em><em> </em><em> </em><em>2cot2x</em>

4 0
3 years ago
What is mythology and therefore why is it important?​
Mrrafil [7]

Answer:

mythology is important for both individualistic and collective reasons. On an individual level, mythology could teach moral or human truths, whereas on a collective level mythology could be used to keep people in touch with their origins. Mythological stories could then be used to teach children values such as hard work, diligence and obedience.

Step-by-step explanation:

6 0
3 years ago
A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre
Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

N=2.85 rev/s

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distance of objects from stool r_1=0.789 m

Combined moment of inertia of stool and student =5.53 kg.m^2

Now student pull off his hands so as to increase its speed to 3.60 rev/s

\omega _2=2\pi N_2

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Initial moment of inertia of two masses I_0=2mr_^2

I_0=2\times 1.5\times (0.789)^2=1.867

After Pulling off hands so that r' is the distance of masses from stool

I_0'=2\times 1.5\times (r')^2

Conserving angular momentum

I_1\omega =I_2\omega _2

(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62

I_0'=1.397\times 0.791

I_0'=5.851

5.53+2\times 1.5\times (r')^2=5.851

2\times 1.5\times (r')^2=0.321

r'^2=0.107009

r'=0.327 m

7 0
3 years ago
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