Answer:
f
(
2
)
=
20
Explanation:
To evaluate f
(
2
)
substitute x = 2 into f
(
x
)
f
(
2
)
=
(
×
2
2
−
(
4
×
2
×
x
=
28−
8
=
20
So, first we multiply the fraction by using the formula a/b times c/d= a times c/b times d
=(y^2-16) times 5y/2y(y-4)
Now, we cancel the common factor y
=(y^2-16) times 5/2(y-4)
Now, we factor 5(y^2-16)
We factor (y^2-16) first
y^2-16
Rewrite 16 as 4^2
y^2-4^2
Now, apply the formula x^2-y^2=(x+y)(x-y)
=y^2-4^2=(y+4)(y-4)
=5(y+4)(y-4)
=5(y+4)(y-4)/2(y-4)
Cancel the common factor y-4
=5(y+4)/2
Answer: 5(y+4)/2
Answer: Variables
F and C are placeholders for numbers. They are called variables because they are allowed to vary, or change. If you change C then it affects F, and vice versa. If the values for the placeholders is not allowed to change, yet it holds a number, then it is considered a constant. In this case, we don't have constants or else the formula isn't too useful.
Step-by-step explanation:
5.4×-0.9=n
n=-4.86
(-4/5)/(1/3)=x
X=-2 2/5
