Answer:
176 199 pounds
Step-by-step explanation:
To answer this it is first useful to find the proportionality constant.
F= kx
8080 pounds = k.88 in
k = 91.81 pound/inch
So what force is required to stretch the spring to 1919 inches?
F = kx
= 91.81 pound/inch * 1919 inches
= 176 199 pounds
It is worth noting that this force seems rather large and the spring might have long reached its elastic limit
41 hours of class I guess so
A hyperbola with a center at (0, 0) can be defined as x²/a² − y²/b² = ±1.<span>
</span>The statement "<span>The symmetry of a hyperbola with a center at (h, k) only occurs at y = k" </span>is false, because a hyperbola have many different orientations.
It doesn't have to be symmetric about the lines y = k or x = h.
Answer: 
Step-by-step explanation:
Given
Length L=15 feet
width b=2 feet
Volume V=375 cubic feet
Suppose h is the height
Volume is given by 
