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bazaltina [42]
3 years ago
6

1. Which of the following options will allow you to insert a quick table? (1 point) Insert ribbon > Shapes drop-down menu

Computers and Technology
2 answers:
emmasim [6.3K]3 years ago
5 0
Quick tables are tables<span> that are stored in galleries as building blocks and can be reused and accessed at any time.</span>
The following option will allow you to insert a quick table:
Insert ribbon -> Table drop-down menu

Yous should click on the ribbon (tab) Insert and then from the Table drop-down in the Tables group, select Quick Tables.
JulijaS [17]3 years ago
4 0
B its on mic microsofts website

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Write about storage<br>(should be in easy words)​
enyata [817]

Answer:

Answer to the following question is as follows;

Explanation:

The process of storing digital information in a data storage media using computing technology is known as storage. Storage is a technique that allows a computer to keep data indefinitely or intermittently. Computer storage capacity and electronic data management are other terms for storage.

6 0
2 years ago
When saving a document or drawing, you determine the destination folder in which the file will be saved by?
bekas [8.4K]

making a selection in the Save in: box.<span>

</span>
8 0
3 years ago
A string variable can hold digits such as account numbers and zip codes.<br><br> FALSE<br><br> TRUE
gavmur [86]
True. The second one is right
6 0
3 years ago
What is the formula for determining the number of possible hosts on a network?
fredd [130]
2**(32 - netmask) - 2 = number of nodes available

The netmask is in CIDR (Common Internet Domain Routing) notation, without the slash.

One of the nodes would be needed for a router or else you can't communicate with other networks.
3 0
3 years ago
Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type
sattari [20]

Solution :

#include  $$

#include $$

#include $$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal$\text{To}$Binary(char* hexdec)

{

 

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$(sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

 

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0
2 years ago
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