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Elan Coil [88]
3 years ago
6

Tim bought a pen for $2.25, a pencil for $0.59, a notebook for $6.49, and a highlighter for $1.49. He used a coupon that gave hi

m $5.25 off his entire purchase. How much did he spend in total?
Mathematics
1 answer:
IrinaK [193]3 years ago
3 0
Add together the prices: $10.82. This is reduced by the value of the coupon: 10.82-5.25=$5.57.
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A silver ring has a volume of 3 cm- and a mass of 36 grams.<br>Find the density of the silver.​
siniylev [52]
M/V = D. 36g/3cm = 12
8 0
3 years ago
With words, we might say: "After 7.5 seconds, Cannon Man was 6.15 feet off the ground."
ValentinkaMS [17]

Answer:

f(7.5)=6.15

Step-by-step explanation:

x=7.5

y= 6.15

Without words you might not understand what is being asked to do.

Well, it has notation in it so when it is turned into function notation you will know how to reverse it and put it back the same way.

6 0
3 years ago
Efectúa la siguientes operaciones 3254+535​
fredd [130]

Answer:

3789

Step-by-step explanation:

3 0
3 years ago
The original price p of an item less a discount of 15%
Snowcat [4.5K]
P-.15p this is the expression for cost after discount

and its just .15p for just the discount

7 0
3 years ago
Read 2 more answers
The larger of two numbers is twice the smaller increased by five. Find the two numbers if three times the larger exceeds double
irina [24]

The larger number is 13 and smaller number is 4

<em><u>Solution:</u></em>

Let the larger number be "a"

Let the smaller number be "b"

<em><u>Given that larger of two numbers is twice the smaller increased by five</u></em>

larger number = twice the smaller increased by five

larger number = twice the smaller number + 5

a = 2b + 5 --- eqn 1

<em><u>Also given that three times the larger exceeds double the smaller by 31</u></em>

Here "exceeds" denotes addition and "times" denotes multiplication

"double" denotes being multiplied by 2

three times the larger number = double the smaller number + 31

3a = 2b + 31 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "b"</u></em>

Substitute eqn 1 in eqn 2

3(2b + 5) = 2b + 31

6b + 15 = 2b + 31

6b - 2b = 31 - 15

4b = 16

<h3>b = 4</h3>

From eqn 1,

a = 2b + 5

a = 2(4) + 5

a = 8 + 5

<h3>a = 13</h3>

Thus the larger number is 13 and smaller number is 4

5 0
3 years ago
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