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hodyreva [135]
3 years ago
6

Help needed ASAP will give you BRAINLIEST and 5 stars RATE

Mathematics
2 answers:
Olin [163]3 years ago
6 0

Answer:

C) problem-solution

Step-by-step explanation:

The writer would give the problem:

dangerous levels of pollution in our oceans

and then the solution:

how people can reduce these levels

larisa [96]3 years ago
4 0

Answer:

C) problem-solution

Step-by-step explanation:

If this helped mind giving me a like?

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FromTheMoon [43]
24. you divide 48 by 2 to get the answer
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Please help asap im so confused
Dmitry_Shevchenko [17]

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C

Step-by-step explanation:

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Which statement is true regarding the graphed functions? f(0) = g(0) X f(-2) = g(-2) f(0) = g(-2) f(-2) = g(0)​
Vanyuwa [196]

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a

Step-by-step explanation:

7 0
3 years ago
Find the probability for the experiment of tossing a coin three times. Use the sample space S = {HHH, HHT, HTH, HTT, THH, THT, T
myrzilka [38]

Answer:

1) 0.375

2) 0.375

3) 0.5

4) 0.5

5) 0.875

6) 0.5                          

Step-by-step explanation:

We are given the following in the question:

Sample space, S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

1. The probability of getting exactly one tail

P(Exactly one tail)

Favorable outcomes ={HHT, HTH, THH}

\text{P(Exactly one tail)} = \dfrac{3}{8} = 0.375

2. The probability of getting exactly two tails

P(Exactly two tail)

Favorable outcomes ={ HTT,THT, TTH}

\text{P(Exactly two tail)} = \dfrac{3}{8} = 0.375

3. The probability of getting a head on the first toss

P(head on the first toss)

Favorable outcomes ={HHH, HHT, HTH, HTT}

\text{P(head on the first toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

4. The probability of getting a tail on the last toss

P(tail on the last toss)

Favorable outcomes ={HHT,HTT,THT,TTT}

\text{P(tail on the last toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

5. The probability of getting at least one head

P(at least one head)

Favorable outcomes ={HHH, HHT, HTH, HTT, THH, THT, TTH}

\text{P(at least one head)} = \dfrac{7}{8} = 0.875

6. The probability of getting at least two heads

P(Exactly one tail)

Favorable outcomes ={HHH, HHT, HTH,THH}

\text{P(Exactly one tail)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

3 0
3 years ago
Show your solution read the instructions​
Annette [7]

Answer:

1) 5r + 2 < s

2) 12t + 6s < 960

3) p - q > 30

Step-by-step explanation:

1) Length of a ruler = r

Height of Shiela = s

According to the question ,

5 times the length of a ruler increased by 2 .

⇒ 5r + 2

Also , 5r + 2 is less than height of Shiela.

Hence , the linear inequality is ⇒ 5r + 2 < s

2) Let the cost of each t-shirt be 't' & cost of each short be 's'.

⇒ Cost of dozen of t-shirts = 12t and Cost of half a dozen shorts = 6s

According to the question ,

12t & 6s is not greater than Php 960.

Hence the linear inequality is ⇒ 12t + 6s < 960

3) Let the number of Php 100-peso tickets be 'p' and let the number of Php  50-peso tickets be 'q'.

According to the question ,

Difference of p & q is not less than 30

Hence the linear inequality is ⇒p - q > 30

8 0
3 years ago
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