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Murljashka [212]

3 years ago

7

The school choir is going on a field trip to see an opera. There are 34 students and 5 teachers going on the trip. If each ticke

t costs $9.50, about how much money do they need to raise to pay for the cost of the trip?

1 answer:

Effectus [21]3 years ago

7 0

Answer:

They have to raise $370.5

Step-by-step explanation:

You add 34 and 5. Then you multiple 39 and 9,50 to get your answer.

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A jet ski company charges a flat fee of $24.00 plus $2.25 per hour to rent a jet ski. Another company charges a fee of $23.00 pl

Zarrin [17]

The advantage of the graphing calculator is that you just have to find two independent equations, introduce them in the calculator and it will find the intersection point ot the two graphs.

The equations that you have to introduce are:

1) y = 2.25x + 24

2) y = 2.75x + 23

The algebraic solution, which will give you the same coordinates of the intersection point of the graphs is

2.25x + 24 = 2.75x + 23

2.75x - 2.25x = 24 - 23

0.5x = 1 => x 1 /0.5 = 2.

Answer: 2

6 0

3 years ago

Find the first six terms of the sequence.

Yuliya22 [10]

Answer:

6, 12, 24, 48, 96, 192

Step-by-step explanation:

The first term a1 = 6 and the common ratio is 2.

So it is 6, 6*2, 6*2^2 ....

8 0

3 years ago

The ratio of boys to girls who play soccer in Mr. Fraser’s class is 14:6. If there were 400students in the school, how many boys

ollegr [7]

Answer:

280

Step-by-step explanation:

Set up a ratio to solve.

Mr. Fraser's class has 20 soccer playing students, and 14 are boys.

14/20 = x/400

Cross multiply. 20x= 5600

Divide by 20 to solve

x= 280

5 0

2 years ago

Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find

densk [106]

Answer:

x=4

Step-by-step explanation:

<u>Step 1</u>:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

$AC^2 = AB^2 + BC^2$

<u>step 2:-</u>

The hypotenuse is longest side is AC = 17 units

(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

$(a + b)^2 = a^2 +2ab+b^2$

289 = 4x^2 +9(x^2+2x+1)

$13x^2 +18x-280 = 0$

finding factors 70 X 52 = 3640

$13x^2 +70x-52x-280 = 0$

$13x^2 -52x+ 70x-280 = 0$

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

x=4 and $13x =-70$

x=4 and $x=\frac{-70}{13}$

we can not choose negative value so x value is 4

Final answer:- x = 4

<u>verification:-</u>

<u></u> $AC^2 = AB^2 + BC^2$ <u></u>

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

289=289

6 0

3 years ago

Read 2 more answers

PLEASEEEE HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

AleksAgata [21]

Angle NBW is 34 so do the math

4 0

2 years ago