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3 years ago

Help please math problem

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

7 0

Answer:

Hope this will help you and hope you understand my handwriting

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4 1/2 + 1 + 2 + 1 1/2 + 4 + 1/2

mafiozo [28]

Your answer would be 17 1/2

7 0

3 years ago

Find the general solution to 3y′′+12y=0. Give your answer as y=... . In your answer, use c1 and c2 to denote arbitrary constants

lozanna [386]

Answer:

$y(x)=c_1e^{2ix}+c_2e^{-2ix}$

Step-by-step explanation:

You have the following differential equation:

$3y''+12y=0$ (1)

In order to find the solution to the equation, you can use the method of the characteristic polynomial.

The characteristic polynomial of the given differential equation is:

$3m^2+12=0\\\\m^2=-\frac{12}{3}=-4\\\\m_{1,2}=\pm2\sqrt{-1}=\pm2i$

The solution of the differential equation is:

$y(x)=c_1e^{m_1x}+c_2e^{m_2x}$ (2)

where m1 and m2 are the roots of the characteristic polynomial.

You replace the values obtained for m1 and m2 in the equation (2). Then, the solution to the differential equation is:

$y(x)=c_1e^{2ix}+c_2e^{-2ix}$

4 0

3 years ago

The owner of an apple orchard would like to estimate the mean number of usable apples produced per tree in his

posledela

Step-by-step explanation:

know the normal large sample condition is not met and also there are outliers

7 0

3 years ago

Suppose F⃗ (x,y)=⟨ex,ey⟩F→(x,y)=⟨ex,ey⟩ and CC is the portion of the ellipse centered at the origin from the point (0,1)(0,1) to

Rudik [331]

Probably the intended ellipse is the one with equation

$\dfrac{x^2}{49}+y^2=1$

We can parameterize $C$ as a piece of this curve by

$\vec r(t)=\langle7\sin t,\cos t\rangle$

with $0\le t\le\frac\pi2$ . Then

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^{\pi/2}\langle e^{7\sin t},e^{\cos t}\rangle\cdot\langle7\cos t,-\sin t\rangle\,\mathrm dt$

etc

7 0

3 years ago

Find (f ° g)(0). *

atroni [7]

Answer:

Step-by-step explanation:

Remark

I have to represent f(x) as plus +f(x)

I like to show this situation as +f(g(x)) which I think is much clearer.

+f(x) = 5x - 4

Solution

+f(g(x)) = 5(g(x)) - 4 What has happened is that wherever you see an x on the right you put in g(x).

Now on the right, you put whatever g(x) is equal to.

+f(g(x)) = 5(x^2 - 1) - 4

Remove the brackets.

+f(g(x)) = 5x^2 - 5 - 4

And make x = 0

+f(g(0)) = 5*0 - 5 - 4

+f(g(0)) = - 9

8 0

2 years ago