R = { (x,y): 3x-y=0 }
The condition is 3x=y so that's not going to be any of these things.
R is reflexive if (x,x)∈R for all x. Let's check.
3x - y = 3x - x = 2x ≠ 0 necessarily. NOT REFLEXIVE
R is symmetric if (x,y)∈R → (y,x)∈R. Let's check.
(x,y)∈R so
3x-y = 0
y = 3x
Is (y,x)∈R. That would be true if 3y-x=0
3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC
R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R. Let's check.
3x-y = 0 so y=3x
3y-z = 0 so z=3y = 9x
3x - z = 3x - 9x = -6x ≠ 0 necessarily NOT TRANSITIVE
Answer:
y= - frac4/7 x + frac9/7
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Because there is three numbers
4*200+4*70+4*5, or you can just use a calculator.
Answer:
y = -
x + 1
Step-by-step explanation:
y = mx + b
Find two point on the graph (0,1) (4,-2); 1 is the y intercept
y = mx + 1
= 
y = -x + 1
