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ryzh [129]
2 years ago
14

Pythagorean Theorem Level 2

Mathematics
1 answer:
Flura [38]2 years ago
3 0

Answer:

10

Step-by-step explanation:

Pyth. Theorem:

a = leg, b = leg, c = hypotenuse

c =  \sqrt{ {a}^{2}  +  {b}^{2} }

The length of the third side

=

\sqrt{ {5 \sqrt{3} }^{2} +  {5}^{2}  }

=

\sqrt{75 + 25}

=

\sqrt{100}

= 10

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Bryan invests $500 in an account earning 4% interest that compounds annually. If he makes no additional deposits or withdrawals,
kompoz [17]

As the question is not clear about the calculation needed, so i will calculate in both ways - compound interest and simple interest.

Given are:

Amount = $500

Rate of interest = 4% or 0.04

Time = 25

n = 1(compounded annually)

Formula for compound interest :

A=P(1+\frac{r}{n})^{nt}

Putting values in the formula:

A= 500(1+\frac{0.04}{1})^{25}

= 500(1.04)^{25}

= 500*2.665 = $ 1332.50

Hence, amount in the account after 25 years = 500+1332.50= $1832.50

Formula for simple interest:

S.I.=\frac{p*r*t}{100}

= \frac{500*4*25}{100}

Interest = 500

Hence, amount in the account after 25 years = 500+500 = $1000

4 0
3 years ago
Of the 32 students in a class, 18 play the violin, 16 play the piano, and 7 play neither.
german

Answer:

(a)9

(b)I. 0.28125

II. 0.46875

III. 0.25

Step-by-step explanation:

There are a total of 32 students, therefore the number of elements in the Universal set, n(U)=32

1$8 play the violin, n(V)=18\\16 play the piano, n(P)=16\\ 7 play neither, n(P \cup V)' =7

(a)The Venn diagram is attached below.

n(U)=n(V)+n(P)-n(V \cap P)+ n(P \cup V)'\\32=18+16+7-n(V \cap P)\\32=41-n(V \cap P)\\n(V \cap P)=41-32\\n(V \cap P)=9\\

Therefore, 9 students play both the violin and  piano.

(b)

I. Probability that the student  plays the violin but not the piano

Number of Students who play violin only =18-x=18-9=9

P(V \cap P') = \dfrac{n(V \cap P')}{n(U)}\\= \dfrac{9}{32}\\=0.28125

ii.Probability that the student does not play the violin

Number of Students who does not play violin only =17-x+7=17-9+7=15

P(does not play violin only)

= \dfrac{15}{32}\\=0.46875

iii.Probability that the student plays the piano but not the violin

Number of Students who play piano only =17-x=17-9=8

P(V' \cap P) = \dfrac{n(V' \cap P)}{n(U)}\\= \dfrac{8}{32}\\\\=0.25

3 0
2 years ago
Prove that there is a positive number x such that x^3=5
astra-53 [7]

x^3=5\\ x=\sqrt[3]5


and \sqrt[3]5 is positive

7 0
3 years ago
Type the number to the left of the rational number in the box to the point it represents on the number line.
morpeh [17]

Is it a picture or an answer or something

3 0
3 years ago
What is tan(θ/2), when tan(θ) = 4/3 and when π < θ < 3π/2?
Tamiku [17]
Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
 then,  Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.

tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]

Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9)        (sec²Ф will have a negative value, because Ф is in the        sec Ф=-5/3                                 third quadrant).

cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5

Therefore:

tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2

Answer: tan (Ф/2)=-2; when tan (Ф)=4/3


3 0
2 years ago
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