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3 years ago

Pythagorean Theorem Level 2

Mathematics

1 answer:

Flura [38]3 years ago

3 0

Answer:

Step-by-step explanation:

Pyth. Theorem:

a = leg, b = leg, c = hypotenuse

$c = \sqrt{ {a}^{2} + {b}^{2} }$

The length of the third side

$\sqrt{ {5 \sqrt{3} }^{2} + {5}^{2} }$

$\sqrt{75 + 25}$

$\sqrt{100}$

= 10

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The graphs of f(x)=2x+4 and g(x)=10−4x intersect at (1, 6) .

iren [92.7K]

2x+4=10-4x

-2x+4=10

-2x=6

X=-3

8 0

4 years ago

Read 2 more answers

What percentage of 3 is 4?

Artyom0805 [142]

Answer:

13.333% of 3 is 4.

Step-by-step explanation:

Take missing value = x

x% of 3 = 4

x/100 × 3 = 4

3x/100 = 4

3x = 400

x = 400/3

x = 13.333

Hope it helps ⚜

5 0

2 years ago

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What is the product of (7/8)(-16)(-7)(-1/14) A -7 B -9/16 C -1/7 D 23/12

Nat2105 [25]

Answer:

-7

Step-by-step explanation:

(7/8)(-16)(-7)(-1/4)

(7/8)(-1/4)(-16)(-7)

(-1/16)(112)

-7

4 0

3 years ago

Please please help me

Gala2k [10]

Answer:

89.0°

Step-by-step explanation:

The segment from the centre of the circle to the chord is a perpendicular bisector, hence

third side of right triangle = 12.7 ÷ 2 = 6.35

The angle subtended at the centre by arc CD is twice the angle subtended by the right triangle at the centre

The triangle from the centre to C is congruent to the triangle from the centre to D

Calculate the angle (Θ ) in the right triangle using the sine ratio

sinΘ = $\frac{opposite}{hypotenuse}$ = $\frac{6.35}{9.06}$

Θ = $sin^{-1}$ ( $\frac{6.35}{9.06}$ ) ≈ 44.5°

Hence

measure of CD = 2 × Θ = 2 × 44.5 = 89.0°

5 0

4 years ago

Four brothers have ages which are consecutive even integers. If the product of the ages of the two middle brothers is 528, how o

exis [7]

Answer:

The oldest brother is of age $26$ years.

Step-by-step explanation:

As the age of four brothers are consecutive even integers.

We assume that the ages are $x,(x+2),(x+4),(x+6)$ as their respective ages.

And the age of the youngest brother $x$ yrs.

Age of the oldest brother $(x+6)$ yrs.

According to the question

Product of two middle brother that is $(x+2)(x+4) =528$

So we will arrange this in our equation and solve the quadratic.

$(x+2)(x+4) =528$

$x^{2}+4(x)+2(x)+8 =528$

$x^{2}+4(x)+2(x)+8-528=0$

$x^{2}+6(x)-520=0$

Solving the quadratic by using middle term splitting or directly with quadratic formula we can find the value of 'x' .

Here it is solved with quadratic formula:

Comparing with standard equation $ax^{2}+b(x)+c=0$ ,here $a=1,b=6\ and\ c=-520$ .

$x= \frac{-b \pm \sqrt{b^2-4ac} }{2a} = \frac{-6 \pm \sqrt{6^2-4\times \ (-520)} }{2\times 1}$

$x=20,-26$

We will work with the positive value of (x) so the the age of the youngest brother $=(x)=20$ yrs.

And the age of the the oldest brother $=(x+6)=(20+6)=26$ years.

The age difference is of $(26-20)=6$ years.

4 0

4 years ago