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3 years ago

Let f(x) = 9x3+ 21x2^ - 14 and g(x) = 3x + 1. Find "f (x) over g (x)

Mathematics

1 answer:

kondor19780726 [428]3 years ago

7 0

Answer:

$\frac{f(x)}{g(x)}=3x^2+6x-2-\frac{12}{3x+1}$

Step-by-step explanation:

The first function is $f(x)=9x^3+21x^2-14$

The second function is $g(x)=3x+1$ .

$\frac{f(x)}{g(x)}=\frac{9x^3+21x^2-14}{3x+1}$

We perform the long division as shown in the attachment to obtain the quotient as: $Q(x)=3x^2+6x-2$ and remainder $R=-12$ .

Therefore:

$\frac{f(x)}{g(x)}=3x^2+6x-2-\frac{12}{3x+1}$

where $x\ne -\frac{1}{3}$

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If angle 1 is 140°, then find the measure of the other angles.

Vlad [161]

<h2>Angles</h2>

<h3>If angle 1 is 140°, then find the measure of the other angles.</h3>

∠2 = 40°
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∠7 = 40°
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Explanation:

The relationship between ∠1 and ∠2 are supplementary angles, so when you add up their measurements, it will become 180°. Simply subtract 180 and 140 to get the measure of ∠2. As well as ∠3, they're linear pairs. And they are also supplementary. To determine the measure of ∠6 and ∠7, notice the relationship between ∠2 and ∠6. As you noticed, it is corresponding angles. So they have the same measurement. If ∠2 = 40°, then ∠6 = 40°. As well as ∠7, because the relationship between ∠6 and ∠7 are vertical pairs. So the angle measurement of ∠7 is also 40°.

Meanwhile, the relationship between ∠1 and ∠4 are vertical pairs. It means they also have the same measurement. So ∠4 = 140°. The relationship between ∠1 and ∠5 are corresponding angles, so they also have the same measurement. If ∠1 = 140°, then ∠5 = 140°. The relationship between ∠1 and ∠8 are alternate exterior angles, and they also have the same measurement. If ∠1 = 140°, then ∠8 = 140°.

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Answer:

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Step-by-step explanation:

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3 years ago

Let f(x) = 9x3+ 21x2^ - 14 and g(x) = 3x + 1. Find "f (x) over g (x)​

Let f(x) = 9x3+ 21x2^ - 14 and g(x) = 3x + 1. Find "f (x) over g (x)