Helpp plzzz I will mark brainliestttt
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Given:
A figure of an isosceles trapezoid with bases 18 and 24, and the vertical height is 4.
To find:
The legs of the isosceles trapezoid.
Solution:
Draw another perpendicular and name the vertices as shown in the below figure.
From the figure it is clear that the AEFD is a rectangle. So,
Since ABCD is an isosceles trapezoid, therefore in triangle ABE and DCF,
(Legs of isosceles trapezoid)
(Vertical height of isosceles trapezoid)
(Right angle)
(HL postulate)
(CPCTC)
Now,
Using Pythagoras theorem in triangle ABE, we get
Taking square root on both sides, we get
Side length cannot be negative. So, .
Therefore, the length of legs in the given isosceles trapezoid is 5 units.
From the question, we know the population standard deviation, σ = 1.63, the sample standard deviation, s = 3.07, the sample mean, 
and the sample size, n = 38.
The question illustrates a hypothesis chi-square test of variance.
The test statistics for a Chi-squared test of variance is given by
The question illustrates a hypothesis chi-square test of variance.
The test statistics for a Chi-squared test of variance is given by