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Furkat [3]
3 years ago
9

How will the area of the circle change if it is dilated by a scale factor of 1/2? The area will be 2 times greater than the orig

inal. The area will be 4 times greater than the original. The area will be 1/4 the original. The area will be 1/2 the original.
Mathematics
2 answers:
coldgirl [10]3 years ago
7 0
We know that

[scale factor]=1/2
[dilated area of circle]=[original area of circle]*[scale factor]²
so
[dilated area of circle]=[original area of circle]*[1/2]²
[dilated area of circle]=[original area of circle]*[1/4]

therefore

the answer is
<span>The area will be 1/4 the original</span>
devlian [24]3 years ago
4 0
<span>The area will be 1/4 the original.
</span><span>
Is the CORRECT answer^^^^^


</span>
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Answer:

A. 8 complete hotdogs were made.

B. The wiener.

C. The bun.

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1 complete hotdog = 1 wiener + 1 bun

You have, 3*10 bun and 8 wiener

= 30 bun and 8 wiener

A. Since, we have 30 bun and 8 wiener and for 1 complete hotdog = 1 wiener + 1 bun

Therefore, 8 hotdogs = 8 wiener + 8 buns

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B.

Since 8 complete hotdogs are made, 8 wiener and 8 buns are used.

Therefore, the limiting ingredient is the wiener because it is the smallest number of ingredient and none of it was left after making the 8 hotdogs.

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The buns is the leftover ingredient

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4 years ago
Sin^-1(1/2)<br> Please help I don't know how to do inverse or arcs<br> Thanks
Anit [1.1K]

Answer:

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6 0
3 years ago
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iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

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Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

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3 years ago
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Answer:

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