Sorry I can’t buddy........................................................:(
Answer:
8) answer=5 9)answer=15
Step-by-step explanation:
all you have to do is replace in the following formula
Where
X1: is the first number of the first point
Y1: is the second number of the first point
X2: is the first number of the second point
Y2: is the second number of the second point
you replace in the formula and solve
I attach solution
Let the numbers be n, n+2, n+4
Sum equals too= 13+2(n+4), which is 2n+21
a) Equation--> n+n+2+n+4= 2n+21
b) Solution--> 3n+6= 2n+21
=> n= 15
c) Second number--> 17 (15+2)
Third number--> 19 (15+4)
d) 15+15+2+15+4=30+21
=> 51= 51
So, the equation is true.
And pls mark me brainliesttt :)))
I got 2.29 is the difference and debras cows made more obviously
Fraction form is 229/100
MARK ME BRAINLIEST PLEASE
Given that PQ and RS are drawn with KL as tranversal intersecting PQ at M and RS at point N. Angle QMN is congruent to angle LNS because they are alternate to each other. The theorem that Kari can use to show that the meansure of QML is supplementary to the measure of angle SNK is Alternate Exterior Angles Theorem.
This is because angle KNR is equal to QML by alternate exterior angles theorem so is angle MLP and SNK
