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Irina-Kira [14]
3 years ago
12

I’m really confused on this problem.

Mathematics
1 answer:
marysya [2.9K]3 years ago
8 0
The area of the rectangle is 32 cm squared and the area of the triangle is 22 cm squared. When you add them together you get the area of the entire figure, which is 54 cm squared
Hope this helps!








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Linda and Juan went shopping. Linda spent $14 less than Juan.
Rudiy27

Answer: Let x = amount Linda spent.

x=y-$18

Step-by-step explanation:

7 0
3 years ago
Monthly sales of an SUV model are expected to increase at the rate of S′1t2 = -24t 1>3 SUVs per month, where t is time in mon
uysha [10]

The company will continue to manufacture this model for 19 months.

The question is ill-formatted. The understandable format is given below.

An SUV model's monthly sales are anticipated to rise at a rate of

S'(t)=-24^{1/3} SUVs each month, where "t" denotes the number of months and "S(t)" denotes the monthly sales of SUVs. When monthly sales of 300 SUVs are reached, the business intends to discontinue producing this model.

Find S if monthly sales of SUVs are 1,200 at time t=0 (t). How long will the business keep making this model?

Given S'(t)=-24^{1/3} ... ... (1)

Condition (1) at t=0; s(t) =1200

We find S(t)=300 then t=?

a) We find S(t)

from S'(t)=-24^{1/3}

\implies \frac{dS(t)}{dt}=-24t^{1/3} ~~[\because X'(t)=\frac{dX}{dt} \\\implies dS(t) = -24t^{1/3}dt\\

On Integrating both sides

S(t)=-18t^{4/3}+c ~...~...~(2)

Now, at t=0 then S(t)=1200

So, from (2)

1200=0+c

⇒c=1200

\thereforefrom eq (2)

S(t)=-18t^{4/3}+1200 ~...~...~(3)

b) Considering that the firm intends to cease production of this model once monthly sales exceed 300 SUVs.

So, take S(t)=300

from eq (2) 300=-18t^{4/3}+1200

t^{4/3}=\frac{1200-300}{18}\\=\frac{900}{18}=50\\\implies t=50^{3/4}\\\implies t=18.8030

Hence the company will continue 18.8020 months.

Learn more about integration here-

brainly.com/question/18125359

#SPJ10

8 0
2 years ago
50 POINTS SHOW YOUR WORK
aliya0001 [1]

Answer:

The % growth rate is 15.8%.

Step-by-step explanation:

Let the function is given by f(w) = a(b)^{w}, where f(w) is the number of a specific product produced after w weeks.

Now, given for w = 0, f(0) = 190 = a

So, the function becomes f(w) = 190(b)^{w} ............. (1)

Now, it is also give that at w = 1, f(1) = 220.

So, from equation (1) we get,

220 = 190 (b)^{1} = 190b

⇒ b = 1.15789.

Now, b = 1 + r

⇒ 1.15789 = 1 + r

⇒ r = 0.15789

Therefore, the % growth rate is 0.15789 × 100% = 15.8% (Approx.)

8 0
3 years ago
Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B24%20%5Ctimes%205%20%2B%201%7D%20" id="
Orlov [11]

Answer:

your answer will be 11

Step-by-step explanation:

Thanks again!!

4 0
3 years ago
Read 2 more answers
Solve the equation below for the variable (x):
user100 [1]

Answer:

Hope this helps. If not let me know and I'll explain it better

3 0
3 years ago
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