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1 answer:
Answer:
Step-by-step explanation:
1) ABCD is a trapezium. AB ║ CD
∠ADC + ∠DAB = 180° { Co interior angles}
110° + ∠DAB = 180
∠DAB = 180 -110
∠DAB = 70°
2) Sum of all angles of trapezium = 360°
∠A + ∠B + ∠DCB + ∠D = 360
70° + 50° + ∠DCB + 110° = 360
230 + ∠DCB = 360
∠DCB = 360 - 230
∠DCB = 130°
3) For finding the height, use Pythagorean theorem
height² + base² = hypotenuse²
height² + 6² = 10²
height² + 36 =100
height² = 100 - 36
height² = 64
height = √64
height = 8 m
4) a = AB = x m
b = 9 m
h = height = 8 m
Area of trapezium = 120 m²
= 120
x + 9 = 120/4
x + 9 = 30
x = 30 - 9
x = 21 m
AB = 21m
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Answer:
After 3 seconds
Step-by-step explanation:
Given
Required
Time the drop will hit the ground
When the drop hits the ground,
So, we have:
Rewrite as:
Expand
Factorize
Factor out 5t + 1
Split
or
Solve for t
or
Time cannot be negative.
So:
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
Now we can apply the quadratic formula
where a=-16, b=122, and c=198
or 
or 
or 
Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
Lets replace the values into the the vertical motion formula to get:
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
Now we can apply the quadratic formula
Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.