What is the median for the bar graph below? 6 5 4 3

A set X consists of all real numbers greater than or equal to 1. Use set-builder notation to define X.

vitfil [10]

Theory:

The standard form of set-builder notation is 

{ x | “x satisfies a condition” }

This set-builder notation can be read as “the set of all x such that x (satisfies the condition)”.

For example, { x | x > 0 } is equivalent to “the set of all x such that x is greater than 0”.

Solution:

In the problem, there are 2 conditions that must be satisfied:

1st: x must be a real number

In the notation, this is written as “x ε R”. Where ε means that x is “a member of” and R means “Real number”

2nd: x is greater than or equal to 1

This is written as “x ≥ 1”

Answer:

Combining the 2 conditions into the set-builder notation:

X = { x | x ε R and x ≥ 1 }

8 0

3 years ago

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8 freshmen, 9 sophomores, 9 juniors, and 7 seniors are eligible to be on a committee.

loris [4]

Answer: 11113200

Step-by-step explanation:

We know that , the number of combination of choosing r things from n things is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

$^8C_4\times ^9C_5\times^9C_2\times^7C_3$

$=\dfrac{8!}{(8-4)!4!}\times\dfrac{9!}{(9-5)!5!}\times\dfrac{9!}{(9-2)!2!}\times\dfrac{7!}{3!(7-3)!}\\\\ =\dfrac{8\times7\times6\times5\times4!}{4!4!}\times\dfrac{9\times8\times7\times6\times5!}{4!5!}\times\dfrac{9\times8\times7!}{7!2!}\times\dfrac{7\times6\times5\times4!}{3!4!}\\\\=11113200$

∴ The number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors = 11113200

6 0

4 years ago

Which expression is equivalent to (2^3)^-6?

Kay [80]

Answer:

2^-18

Step-by-step explanation:

3 0

2 years ago

1/3 + 1/4 and the the sinplest form

Verizon [17]

The least common multiple between 3 and 4 is 12, so we can use this fact to rewrite both 1/3 and 1/4 in 12ths:

$\big( \frac{1}{3}\times \frac{4}{4}\big) + \big(\frac{1}{4}\times \frac{3}{3}\big)=\\ = \frac{4}{12}+ \frac{3}{12}\\\\ = \frac{7}{12}$

We're left with an answer of 7/12, which can't be reduced.

8 0

3 years ago

ANYONE PLEASE HELP ME WITH MY MATH HOMEWORK I REALLY NEED THE ANSWER RIGHT NOW BECAUSE I HAVE TO PASS THIS LATER I HOPE Y'ALL CA

zubka84 [21]

Answer:

1. 9x^4/14

2. 1

Step-by-step explanation:

simplify

5 0

3 years ago

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