Y=2/1x

Explanation:You start at -4 from the y and go to 6.So that becomes 10. Then you start at -2 from the x then go to 3 which mean you moved 5.So 10/5 simplified is is 2/1

8 0

3 years ago

In 2000, there were 12900 students at college A, with a projected enrollment increase of 900 students per year. In the same year

LenaWriter [7]

Answer:

Step-by-step explanation:

Let x represent the number of years it will take the two colleges to have the same enrollment.

In 2000, there were 12900 students at college A, with a projected enrollment increase of 900 students per year. This means that the expected number of students at college A in x years time is

12900 + 900x

In the same year, there were 25,000 students at college B, with a projected enrollment decline of 700 students per year. This means that the expected number of students at college B in x years time is

25000 - 700x

For both colleges to have the same enrollment,

12900 + 900x = 25000 - 700x

900x + 700x = 25000 - 12900

1600x = 12100

x = 12100/1600

x = 7.56

Approximately 8 years

The year would be 2000 + 8 = 2008

4 0

4 years ago

Solve the system -2y+5z=-3 y=-5x-4z-5 x=4z+4

kow [346]

-2y + 5z = -3
y = -5x - 4z - 5
x = 4z + 4

-2(-5(4z + 4) - 4z - 5) + 5z = -3
-2(-20z - 20 - 4z - 5) + 5z = -3
-2(-20z - 4z - 20 - 5) + 5z = -3
 -2(-24z - 25) = -3
 48z + 50 = -3
 - 50 - 50
 48z = -53
 48 48
 z = -1⁵/₄₈
x = 4(-1⁵/₄₈) + 4
x = -4⁵/₁₂ + 4
x = ⁵/₁₂

y = -5(⁵/₁₂) - 4(-1⁵/₄₈) - 5
y = -2¹/₂ + 4⁵/₁₂ - 5
y = 1¹¹/₁₂ - 5
y = -3¹/₂

(x, y, z) = (⁵/₁₂, -3¹/₂, -1⁵/₄₈)

6 0

4 years ago