All categories

3 years ago

Plz help me. what is 4.9 * 10^-5 +.0005

Mathematics

2 answers:

Molodets [167]3 years ago

8 0

Answer:

It should be 490000.0005

Step-by-step explanation:

4.9*10^5+.0005

10^5=100000

4.9*100000=490000

490000+.0005=490000.0005

AURORKA [14]3 years ago

4 0

Answer:

Step-by-step explanation:

$10^{-5}=\frac{1}{10^{5}}=\frac{1}{100,000}=0.00001\\\\$

4.9* 10^-5 +0.0005 = 4.9 * 0.00001 + 0.0005

= 0.000049 + 0.0005

= 0.000549

You might be interested in

Problem 5 <br><br><br> Please help

Anon25 [30]

90 degrees that’s the answer for this question

4 0

4 years ago

Given the point (-1, 8), answer the questions below: After that point was translated 5 units right and 4 units up, the coordinat

Rom4ik [11]

a) x=4 is 5 units to the right of x=-1.

y=12 is 4 units up from y=8.

Your point (-1, 8) is translated to (4, 12).

___

b) If the parent function f(x) = x is translated so it goes through (4, 12), the translated function can be written ...

... g(x) = f(x-4) +12 = (x -4) +12

... g(x) = x +8

7 0

3 years ago

Give integers p and q such that Nu l font size decreased by 3Nul A is a subspace of set of real numbers R Superscript pℝp and Co

jeka94

Answer:

Please find attached solution.

Step-by-step explanation:

6 0

3 years ago

Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A

liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality $\sin ^2\theta +\cos ^2\theta \geq 1$

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

$\sin \theta$ = side opposite to $\theta$ /hypotenuse

$\cos \theta$ = side adjacent to $\theta$ /hypotenuse

$\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta$

$\cos \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta$

So, coordinates of A = $\left ( \cos \theta ,\sin \theta \right )$

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by $x^2+y^2=1$

Put $(x,y)=\left ( \cos \theta ,\sin \theta \right )$

$\cos ^2\theta +\sin ^2\theta =1$

So, $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ satisfies the equation $x^2+y^2=1$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ inside the circle, $\cos ^2\theta +\sin ^2\theta$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ outside the circle, $\cos ^2\theta +\sin ^2\theta >1$

So, only points on the circle satisfy the given inequality.

4 0

3 years ago

Read 2 more answers

Please help me with this

Vitek1552 [10]

Answer:

A = 6.2831853071796 in $^{2}$

Step-by-step explanation:

Surface area of a capsule:A = 4πr2 + 2πrh.

$A = 4πr2 + 2πrh. \\ a = 4\pi(0.5)2 + 2\pi(0.5)(1) \\ A= 6.2831853071796 \: in {}^{2}$

3 0

2 years ago