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nataly862011 [7]

3 years ago

6

At a certain middle school, there are 26 students per teacher in every homeroom. Is the total number of students proportional to

the number of teachers

1 answer:

Verizon [17]3 years ago

6 0

Yes, because there is a corresponding amount of teachers per student.

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The ratio of adults to children on a field trip is 2:7. If there are 14 adults on the trip, how many children are there?

Bas_tet [7]

Answer:

49 children

Step-by-step explanation:

Adult : Child = 2 : 7

Adult = 14

2 = 14

So, 1 = 14/2 = 1 = 7 in the ratio.

So, 7 x 7 = 49 children are there.

7 0

3 years ago

Read 2 more answers

Icy River increased the price of a $1.15 cola by 15%. Find the increase in price and the new price. round to the nearest cent

madam [21]

15% x
100 1.15 X is your variable, your unknown number and 15% has to always be over 100 , Then you have to cross multiply and divide 100 because that is the only number basically you have to just multiply across and divide 100 to make it to the nearest cent you have to round the last two numbers after the decimal Representing money.. Hope this helps!!

5 0

3 years ago

Calculate the percent.

dimaraw [331]

12%... (3×4)/(25×4) = 12/100... 12/100 = .12 which is 12%

7 0

3 years ago

A car is 180 inches long. A truck is 75% longer than the car. How long is the truck?

LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

The truck is 315 inches long

7 0

3 years ago

Which expression is equivalent to ( 4mn / m^-2n^6)^-2a. n^6 / 16m^8b. n^10 / 16m^6c. n^10 / 8m^8d. 4m^3 / n^8?

Eva8 [605]

$\huge{(} \small{\frac{4mn}{ {m}^{ - 2} {n}^{6} }} \huge{) } \small{{}^{ {}^{ {}^{ {}^{ - 2} } } } }\\ \\ \\ \huge{(} \small{ \frac{4 \times m {}^{1} \times n {}^{1} }{ {m}^{ - 2} \times {n}^{6} }} \huge{)} \small{^{ {}^{ {}^{ {}^{ - 2} } } }} \\ \\ \\ \huge{(} \small{4 \times {m}^{1 - ( - 2)} \times {n}^{1 - 6}} \huge{)} \small{ {}^{ {}^{ {}^{ {}^{ - 2} } } } } \\ \\ \\ \huge{(} \small{ 4 \times {m}^{1 + 2} \times {n}^{ - 5} } \huge{)} \small{ { }^{ {}^{ {}^{ {}^{ - 2} } } } } \\ \\ \\ \small{ {(4)}^{ - 2} \times ({m}^{3} ) ^{ - 2} \times {(n{}^{ - 5} )}^{ - 2} } \\ \\ \\ \frac{1}{ {4}^{2} } \times {m}^{ - 6} \times {n}^{ 10} \\ \\ \\ \frac{1}{16} \times \frac{1}{ {m}^{6} } \times {n}^{10} \\ \\ \\ \frac{ {n}^{10} }{16{m}^{6} }$

$\text{ Hence, option B is correct }$

7 0

4 years ago