Answer:
2
sec
(θ
) − 2
tan
(
θ
)
Step-by-step explanation:
Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
Answer:
Step-by-step explanation:
For 
, we have two cases:
Therefore, for 
, we have the following cases:
Solving, we have:
.
Therefore,
Answer:
This is not descriptive at all..?
Step-by-step explanation:
We need a real question.
Answer:
I believe the answer is 20
Step-by-step explanation:
She rides from her house to school which is 4 kilometers. Then she rides from school to the library which is 6 kilometers. The total so far is 10 kilometers.The question then says she takes the same route home so you would multiple 10 by 2 so the answer should be 20 kilometers
