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Taya2010 [7]
3 years ago
12

I just don't understand how to do number 37.

Mathematics
1 answer:
jeka943 years ago
3 0
So hmmm notice the picture below

get the area of the "square" that contains both triangles
and then subtract the area of that gray triangle

notice the base of the triangle, is just 14, the height is 14

the difference, is the area other two blue smaller triangles

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How to solve this question please helpp!!!!!!<br><br><br> Q1. cos -1 ( - √3/2 )
Amiraneli [1.4K]

Answer:

cos(\sqrt{\frac{3}{2} }) or 0.339

Step-by-step explanation:

6 0
3 years ago
The average maximum monthly temperature in Campinas, Brazil is 29.9 degrees Celsius. The standard deviation in maximum monthly t
velikii [3]

Answer:

3.84% of months would have a maximum temperature of 34 degrees or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29.9, \sigma = 2.31

What percentage of months would have a maximum temperature of 34 degrees or higher?

This is 1 subtracted by the pvalue of Z when X = 34. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 29.9}{2.31}

Z = 1.77

Z = 1.77 has a pvalue of 0.9616

1 - 0.9616 = 0.0384

3.84% of months would have a maximum temperature of 34 degrees or higher

8 0
3 years ago
Helpppp!!!!!! I need this nowwwww
san4es73 [151]
The correct answer is number one
3 0
2 years ago
. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).
devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = \frac{360}{n}

Therefore, angle at the center of a dodecagon = \frac{360}{12} = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = \frac{1}{2}.(a).(b).sin\theta

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = \frac{1}{2}.(3).(3).sin30

= \frac{9}{4}

Area of dodecagon = 12×area of the small triangle

= 12×\frac{9}{4}

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

4 0
2 years ago
Find the value of f(2).
never [62]

Answer:

809-8-90-24+5

Step-by-step explanation:

Find the value of f(2).

y = f(x)

y

10

8

6

4

15

2

-10

-8

-6

-4

-2

2

4

6

5 0
2 years ago
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