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4 years ago

Best buy 1 apple for $0.19 or 3 apple for $0.59?

Mathematics

2 answers:

labwork [276]4 years ago

5 0

Buying 2 apple for $0.19 is better

Mnenie [13.5K]4 years ago

3 0

Buying 1 apple for 19 cents is better.
$3 \times .19 = .57$

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13/10 ÷ 2/10 = ?????

andriy [413]

Answer:

6.5

Step-by-step explanation:

13/10÷2/10= 13/10*10/2

cancel out the 10 and that leaves you with 13/1*1/2=13/2

simplify 13/2 and that leaves you with 6.5

5 0

3 years ago

Read 2 more answers

Find the initial amount a and the decay factor b in the exponential function y=5.05^x

kvasek [131]

Answer:

$a = 5$

$b = .05$

Step-by-step explanation:

Given

$y = 5\ .05^x$

Required

Determine a and b

An exponential function is represented as:

$y =ab^x$

By comparing: $y =ab^x$ with $y = 5\ .05^x$

$a = 5$

$b = .05$

6 0

3 years ago

I need help I dont know how to do this

Nikolay [14]

Answer:

9.2

Step-by-step explanation:

you get 9.1651513... but it says round to the nearest 10th which would be 9.2

7 0

3 years ago

Read 2 more answers

A theme park has a Ferris wheel that takes 2 minutes to go around its 450-foot circumference. The equation · (130) = 450 relates

olchik [2.2K]

Answer: The Ferris wheel’s speed in feet per hour.

Step-by-step explanation:

3 0

3 years ago

Assume y≠60 which expression is equivalent to (7sqrtx2)/(5sqrty3)

Drupady [299]

Answer:

The equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

Step-by-step explanation:

Given the expression

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

Let us solve the expression step by step to get the equivalent

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

$\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=x^{2\cdot \frac{1}{7}}$

$=x^{\frac{2}{7}}$

also

$\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=y^{3\cdot \frac{1}{5}}$

$=y^{\frac{3}{5}}$

so the expression becomes

$\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$ ∵ $\:\frac{1}{y^{\frac{3}{5}}}=y^{-\frac{3}{5}}$

Thus, the equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

5 0

3 years ago