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PolarNik [594]
3 years ago
6

In the simulation, player 2 will always play according to the same strategy. The number of coins player 2 spends is based on wha

t round it is, as described below. (a) You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on. The method returns 1, 2, or 3 based on the following rules. If round is divisible by 3, then return 3. If round is not divisible by 3 but is divisible by 2, then return 2. If round is not divisible by 3 and is not divisible by 2, then return 1. Complete method getPlayer2Move below by assigning the correct value to result to be returned.
Computers and Technology
1 answer:
baherus [9]3 years ago
8 0

The simulation, player 2 will always play according to the same strategy.

Method getPlayer2Move below is completed by assigning the correct value to result to be returned.

Explanation:

  • You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.

#include <bits/stdc++.h>  

using namespace std;

bool getplayer2move(int x, int y, int n)  

{

   int dp[n + 1];  

   dp[0] = false;  

   dp[1] = true;  

   for (int i = 2; i <= n; i++) {  

       if (i - 1 >= 0 and !dp[i - 1])  

           dp[i] = true;  

       else if (i - x >= 0 and !dp[i - x])  

           dp[i] = true;  

       else if (i - y >= 0 and !dp[i - y])  

           dp[i] = true;  

       else

           dp[i] = false;  

   }  

   return dp[n];  

}  

int main()  

{  

   int x = 3, y = 4, n = 5;  

   if (findWinner(x, y, n))  

       cout << 'A';  

   else

       cout << 'B';  

   return 0;  

}

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Answer:

Following are the code to this question:

import random#import package for using random method  

def rolling_dice(): #defining method rolling_dice that uses a random number to calculate and add value in dice1 and dice2 variable

   dice1 = random.randint(1,6)

   dice2 = random.randint(1,6)

   return dice1 + dice2

def rolling(): # defining method rolling

   n_roll = 0  # defining num variable that initial value that is 0.

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   while p > 0 and p < 60: # defining loop that counts value dice value two times  

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       else: # defining else block

           p1 = d # using p1 variable that store d value  

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               if d == 7:#defining if block that checks d value equal to 7

                   p -= p1#subtract the value of p1 in p variable  

                   break # exit loop

               elif d == p:#defining elif block to check d value is equal to p

                   p += p1#adds the value of p1 in p variable  

                   break#using break keyword

   if p<= 0:#defining if block that checks p-value is less then equal to 0  

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Explanation:

In the above-given python code, a method "rolling_dice" is declared, inside the method two-variable "dice1 and dice2" is declared, that uses the random method to calculate the value in both variable and use the return keyword to add both values.

  • In the next step, another method the "rolling"  is declared, inside the method "n_roll and p" is declared that assigns the values and use the two while loop, inside the loop if block is defined that calculates the values.
  • In the next step, a condition block is used that stores value in the p variable and use the print method to print the "n_roll" value.  
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