Answer:
a = -50/51
Step-by-step explanation:
1 + 2a + 3 + 4a + 5 + 6a + ...... + 97 + 98a + 99 + 100a = 0
1 + 3 + 5 + ... + 99 + 2a + 4a + ... + 98a + 100a = 0 Eq. 1
99 + 97 + 95 + ... + 1 + 98a + 96a + ... + 4a + 2a = 0 Eq. 2
Add Eq. 1 and Eq. 2
100 + 100 + ... + 100 + 102a + 102a + ... 102a = 0
50(100)/2 + 50(102a)/2 = 0
2500 + 2550a = 0
2550a = -2500
a = -2500/2550
a = -250/255
a = -50/51
1) c) y = 500 * 2^x
In year 1, x = 1 and the population is 500 * 2^1 = 1000
In year 2, this doubles to 500 * 2^2 = 500 * 4 = 2000
ans so on
This model describes the population doubling every year
2)
A) 3 (1/2)^x and C) (0.25)^x
These numbers reduce as x increases because there is a number with an absolute value less than 1 is being raised to the power of x. They also will never totally reach zero or become negative, but will approach zero as x becomes very large.
Answer:
read the comments i cant help you yet but if you read the comments and do what they say then i can help you
Step-by-step explanation:
The ratio of Isabella’s money to Shane’s money is 3:11
Isabella has $33.
We can make a proportion to solve for how much money Shane has.
A proportion is two ratios that are set equal to each other.
Let’s call Shane’s money ‘S’
We get this proportion: 3/11 = 33/x
If we cross multiply we get:
(33) * (11) = (3) * (x)
Simplifying it, we get:
363 = (3) * (x)
Divide both sides by 3, we get:
x = 121
However, the question asks how much money they have together.
Isabella + Shane = Total
33 + 121 = $154
<span>They have $154 together.</span>
Answer:
You multiply 5 by the exponents and 4^0 is just 1, so 4^45•1=4^45. Hope this helped!
Step-by-step explanation:
