180 and 20 other words eeeee
So,
Let x represent Joe's weight and y represent Jeff's weight.
"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20
"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
(y + 10) + x = 250
We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250
Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250
We will use Elimination by Substitution.
2y - 20 + y + 10 = 250
Collect Like Terms.
3y - 10 = 250
Add 10 to both sides.
3y = 260
Divide both sides by 3.

Substitute again.

Multiply.

Subtract.

Check.
"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.
"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.

1. The tables represent a ratio of 3:5. For example, 6 x 3 = 18, and 6 x 5 = 30. Also, 20 x 3 = 60, and 20 x 5 = 100.
2. The table has a ratio of 3:4, so the missing blank is 64.
Answer:
Step-by-step explanation:
Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42
Let X be the no of passengers who report
X is N(132, 42)
Or Z is 
a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.
the probability that the demand will exceed the capacity of this airplane
=

b) the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers
=
=0.4474+0.3907
=0.8381
c) the probability that the demand for this flight will be less than 100 passengers

d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers
=
e) 79th percentile of this distribution
=
Answer:
infinite solutions
Step-by-step explanation:
Simplify 3x-x-53x−x−5 to 2x-52x−5.
2x-5=2(x+2)-92x−5=2(x+2)−9
2 Expand.
2x-5=2x+4-92x−5=2x+4−9
3 Simplify 2x+4-92x+4−9 to 2x-52x−5.
2x-5=2x-52x−5=2x−5
4 Since both sides equal, there are infinitely many solutions.
Infinitely Many Solutions