In order to solve this problem, we must solve an equation.
First, we need to define our unknown.
Let's call our number "n".
So, the sum of the number and 6 is the same as saying n+6
Then we need to multiply it by 2 (since it's twice the sum)
2(n+6)
This whole thing is equal to three times of the difference of the number and 8
n-8 is equal to the difference between the number and 8, then we need to multiply it by three.
3(n-8)
now, we set both sides equal and solve
The number is 36
Answer:
3
Step-by-step explanation:
3
What do you need help with?
Answer:
Step-by-step explanation:
Left Hand Side
Change to sin(theta) and cos(theta)
csc(theta) = 1/sin(theta)
cot(theta) = cos(theta)/sin(theta)
1/sin(theta) - cos(theta)/sin(theta) Put over Sin(theta) Common denominator
[1 - cos(theta)] / sin(theta) Multiply numerator and denominator by 1 + cos(theta)
(1 - cos(theta)(1 + cos(theta) ) / sin(thata)*(1 + cos(theta))
(1 + cos(theta)(1 - cos(theta)) = 1 - cos^2(theta)
sin^2(theta) / (sin(theta)* ( 1 + cos(theta)
sin(theta) / (1 + cos(theta) )
Right hand Side.
See Above.
