Question

twice the sum of a number and 6 is equal to 3 times the difference of the number and 8. Find the number

Answer 1

In order to solve this problem, we must solve an equation.

First, we need to define our unknown.

Let's call our number "n".

So, the sum of the number and 6 is the same as saying n+6

Then we need to multiply it by 2 (since it's twice the sum)

2(n+6)

This whole thing is equal to three times of the difference of the number and 8

n-8 is equal to the difference between the number and 8, then we need to multiply it by three.

3(n-8)

now, we set both sides equal and solve

$2(n+6)=3(n-8)\\2n+12=3(n-8)\\2n+12=3n-24\\12=n-24\\36=n$

The number is 36