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Luba_88 [7]
4 years ago
15

plzzzz answer right away will mark BRAINLIST AND FIVE STARS PLUS THANKS What is the constant of proportionality in the equation

y = StartFraction x over 9 EndFraction? 0 StartFraction 1 over 9 EndFraction StartFraction 8 over 9 EndFraction 1
Mathematics
2 answers:
guajiro [1.7K]4 years ago
7 0

Answer:

{\sf \frac{1}{9}}

Step-by-step explanation:

y and x are the directly proportional quantities.

\sf y=kx

The constant of proportionality is k.

The equation is:

\sf y=\frac{x}{9}

\sf y=\frac{1}{9} x

The value of k in this equation is:

\sf k= \frac{1}{9}

o-na [289]4 years ago
4 0

Answer:

Proportionality Constant = k = \frac{1}{9}

Step-by-step explanation:

Equation is:

y = \frac{x}{9}

=> y = (\frac{1}{9} ) x

Comparing it with y = kx, where k is the proportionality constant, We get:

Proportionality Constant = k = \frac{1}{9}

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7x-12y=-32 what is the equation of a line parallel to the line shown
Katena32 [7]
7x - 12y = -32
-12y = -7x - 32
y = 7/12x + 8/3...slope here is 7/12. A parallel line will have the same slope.

so ur parallel line will be : y = 7/12x + b....and b can be anything but 8/3...it cannot be 8/3 because then there would be infinite solutions and parallel line do not have infinite solutions, they have no solutions because they do not intersect.
6 0
3 years ago
You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the
il63 [147K]

Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that n = 2809, \pi = \frac{1634}{2809} = 0.5817

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

6 0
3 years ago
What is the value of 11g - 9k + 3 when g = 9 and k = 11?<br> Neatly show your work.
fenix001 [56]

Answer:

3

Step-by-step explanation:

11g - 9k + 3

Let g = 9 and k =11

11 * 9 - 9*11 +3

Multiply

99 - 99 +3

Add

3

4 0
3 years ago
Read 2 more answers
I need help ASAP!!!!!!!
spin [16.1K]

Answer:

left side 7 right side 9

Step-by-step explanation:

it wont just let me tell you the answer

4 0
3 years ago
Can someone help me with questions 1-4
Natalka [10]
1.)
Old Number:35
New Number:45

Now, subract the new number(45) from the old number. (35)

45-35 is 10. Now divide the old number (35) by 10. 
You'll get 3.5. 3.5%, increase is the answer for #1.

2.) Old: s (students)
     New: 36,750

Do 100+5 (Addition because we do not know what the old number is.) 100+5 is 105. Move decimal over twice and you get 1.05. Multiply 36,750 by 1.05.
There were 38,587.5 kids last year.


3.)Since the discount is 15% off, do 100-15=85. Now, move the decimal over from the percent, and that makes that .85. Now multiply 50x.85. You get 42.5, or $42.50. Now the coupon is 10%, So subtract 100-10, giving you 90. Now move the decimal over. .90. Multiply 42.5 (or 42.50) by .90. You get 38.25. You do have enough money.

4.) Subtract 100-15, giving you 85. Move decimal over from percent. .85.
Now you would multiply .85 times k. B should be the answer.

5 0
3 years ago
Read 2 more answers
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