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timurjin [86]
4 years ago
10

Complete the table for the given rule. Rule: y= 1/3x ​

Mathematics
2 answers:
AlladinOne [14]4 years ago
8 0

Answer:

12 - 4

3 - 1

18 - 6

Step-by-step explanation:

This is simply a matter of pluggin in the method, so let's do it shall we?

It wants you to put the a third of each number, so you'll divide each number by three to get what the third is!

VISUAL REPRESENTATION:

12÷3 = 4

3÷3 = 1

18÷3 = 6

umka21 [38]4 years ago
5 0

Hey there!

To complete the table, we need to insert our x into the formula to get our <u><em>output</em></u>, or our y.

1/3(12)=4

1/3(3)=1

1/3(18)=6

I hope that this helps!

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16% of a number is 60. What is that number?<br><br> A375<br> B 432<br> C 456<br> D753
Vlad1618 [11]

Answer:

Its A: 375

Because, if you take 26.6 you have to round it. So, the 6 behind the decimal is over 5 so make the other 6 in front of the decimal a 7. So, the 7 will add 1 to the 2 to make it 3. And i forgot how to get the 5, but trust me dis is right. :3

4 0
3 years ago
How many solutions does the equation have?
snow_lady [41]

5(n - 2) = 5n - 10 \\  \\ 5n - 10 = 5n - 10 \\  \\ 5n - 10 + 10 = 5n - 10 + 10 \\  \\ 5n = 5n \\  \\

Infinite solutions. This equality is true for any value of n.

a.

6 0
3 years ago
Solve for x 1.6 equals 12.8​
xenn [34]

Answer: x=14.4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

6 0
3 years ago
Find the principal.
enyata [817]

Answer:

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Step-by-step explanation:

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8 0
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