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3 years ago

Please help me !!!!!

Mathematics

1 answer:

densk [106]3 years ago

7 0

Step-by-step explanation:

from above figure calculate from the calculator and the right answer will be .....

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the daily low temperature readings for a five-day period were as followed -13, -5 ,6, -7, 9 find the average low temperature for

vivado [14]

First add the numbers together:
-13+(-5),6,(-7),9=-10
Then divide that number by the total # of numbers, which is 5
-10÷5=-2

The average low temperature is -2.

...which is 6th grade stuff, so I am having a hard time believing, that you are in college and/or are having problems with this.

4 0

3 years ago

(05.05 HC) Figure ABCD has vertices A(-3, 2), B(2, 2), C(2, -4), and D(-3, -2). What is the area of Figure ABCD?

irga5000 [103]

Answer:

I don't know how to answer this, sorry!

Step-by-step explanation:

6 0

2 years ago

HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

Logarithm of a power:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

The Logarithm of a Product:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

2 years ago

Tan(θ)/sec(θ) − cos(θ)

myrzilka [38]

Sin(theta)- cos(theta)

4 0

3 years ago

What is the area of this trapezoid? 44 in² 64 in² 168 in² 192 in² Trapezoid A B C D with parallel sides D C and A B. Points F an

devlian [24]

See the attached figure

we know that
[the area of the trapezoid]=[area rectangle]+2*[area triangle]
[the area of the trapezoid]=[14*12]+2*[12*2/2]=192 in²

the answer is 192 in²

5 0

3 years ago

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