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Valentin [98]
2 years ago
7

I am helping my sister with home work and I don’t rennet how to do this. Here is the question-“ there are 24 dogs in the dog sho

w it is the first show for 1/3 of the dogs how many dogs are in the first show
Mathematics
1 answer:
marshall27 [118]2 years ago
4 0
The answer is 8. it's basically just 24÷3
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Do 28.5/42 and 19/28 form a proportion​
Fed [463]

Answer:

Yes they do!

Step-by-step explanation:

Both fractions simplify into approximately 0.68

Hope this helps!

3 0
2 years ago
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Point C has a _____ abscissa and a _____ ordinate.
bulgar [2K]

Abcissa is x, and ordinate is y.

In this case the x is positive, and the y is negative.

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2 years ago
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Which expression is equivalent??? help!
dexar [7]

Answer:

The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

Step-by-step explanation:

Given:

\sqrt[3]{256x^{10}y^{7} }

Solution:

We will see first what is Cube rooting.

\sqrt[3]{x^{3}} = x

Law of Indices

(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}

Now, applying above property we get

\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y   )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})

∴ The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

5 0
3 years ago
How do you estimate21× 78
finlep [7]

21 *78=

20 * 80=

1600 as an estimate


8 0
3 years ago
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ser-zykov [4K]

Answer: 81

Step-by-step explanation:

Mean of four nos = 85

Score = 85 x 4 = 340

Deduct 97 from 340 = 243

Mean of three nos. 243/3 = 81

3 0
2 years ago
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