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abruzzese [7]
4 years ago
7

Please help me on #13

Mathematics
1 answer:
qwelly [4]4 years ago
8 0

Answer:

2.765 Miles is how much he ran

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F(3)= 5x^2 - 4x + 9<br> evaluate this quadratic function
Neporo4naja [7]

Answer:

f(3) = 38

Step-by-step explanation:

Given the quadratic function

f\left(x\right)=\:5x^2\:-\:4x\:+\:9

Evaluating the quadratic function

f\left(x\right)=\:5x^2\:-\:4x\:+\:9

substitute x = 3

f\left(3\right)=\:5\left(3\right)^2\:-\:4\left(4\right)\:+\:9

f(3) = 45-16+9

f(3) = 38

Therefore,

  • f(3) = 38
6 0
2 years ago
Anil completes the 72km journey between Bristol and Cardiff in 48 minutes.
eimsori [14]

total distance travelled=72+69=141

time taken in hours for journey= (48/60)h + (69/60)= 1.95 h

average speed=141km/1.95h= 72.3km/h (3 sf)

5 0
3 years ago
Read 2 more answers
At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad
sertanlavr [38]

<u>Answer:</u>

The length of the person’s shadow is 5.7ft

<u>Explanation:</u>

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the  rules of trigonometry

\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}

\frac{a}{b}=\frac{c}{d}

\frac{35}{50}=\frac{4}{d}

35d=200

d=\frac{200}{35}

d=5.7ft  

Hence, The length of the person’s shadow is 5.7ft.

3 0
3 years ago
In a basketball skills competition, Corson successfully made 5 of 7 shots and Charleigh made 3 of 5
xxTIMURxx [149]

Answer:

Corson had a better performance at the skills competition.

Step-by-step explanation:

In order to determine which player had a better performance at the skills competition, we need to find the percentage performance of both the players.

Therefore,

Corson's percentage performance

=\frac{5}{7}\times 100= 71.43%

Charleigh's percentage performance

=\frac{3}{5}\times 100= 60%

\because Corson's percentage performance > Charleigh's percentage performance

So, Corson had a better performance at the skills competition.

6 0
3 years ago
Please help me. Solve by using substitution.
juin [17]

Answer:

y=-3x+3..........(1)

6x+2y=6

putting value of y

6x+2(-3x+3)=6

6x-6x+6=6

o=0

sorry I do not get answer

6 0
3 years ago
Read 2 more answers
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