Answer:
I think it's choice B and D
Step-by-step explanation:
they both are a straight line and would both have a slope of zero. between point A and D is a slope obviously but D and F would not be the same slope because the line gets steeper. that's how I look at it. I'm pretty sure that's it.
Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
Might be 134 because since angle 2 and 8 are lined up like that it is same side exterior angles which means they are supplementary from each other so they will equal 180. So I did 180-46 to get 134, I’m not sure if I’m correct
Rational ! the number doesn't repeat forever or anything like that. it simplifies nicely.
