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Andrews [41]
3 years ago
6

3y+4y+6=20 can someone please help me with this

Mathematics
1 answer:
Xelga [282]3 years ago
7 0

3y+4y+6=20

(3y+4y)+(6)=20

(Combine Like Terms)

7y+6=20

7y+6=20

Subtract 6 from both sides.

7y + 6 − 6 = 20 − 6

7y = 14

Divide both sides by 7.

7y/7 = 14/7

y = 2

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3 years ago
Find the equation of a line that passes through (0,0) that is perpendicular to 2x+3y=-6
Dovator [93]

The slope-intercept form of a line:

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m - slope

b - y-intercept

Convert 2x + 3y = -6 to the slope-intercet form:

2x+3y=-6         <em>subtract 2x from both sides</em>

3y=-2x-6         <em>divide both sides by 3</em>

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Let k:y=m_1x+b_1 and l:y=m_2x+b_2

l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}

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We have the equation of a line:

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Put the coordinates of the point (0, 0) to the equation:

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Answer: \boxed{y=\dfrac{3}{2}x}


8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%20%2B%20n%7D%7B4%7D%20%20%3D%20%20-%201" id="TexFormula1" title=" \frac{5 + n}{
Delvig [45]

Answer:

n=   -9

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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