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VARVARA [1.3K]
2 years ago
15

In a drawer, there are 6 white socks, 4 black socks, and 2 brown socks. You pick out a

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
5 0

Answer:

D

Step-by-step explanation:

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zlopas [31]
2/3 + 3/4
For this, you want to cross multiply
To do this, you do the first numerator (2) multiplied by the second denominator (4), and the first denominator (3) multiplied by the second numerator (3).If you draw lines between the two numbers you are multiplying, a 'cross' is made. Add these two numbers together to make the new numerator. For the denominator, multiply the bottom two numbers.
Next simplify the new fraction (Follow attached  image)

5 x 3/4
This can be written as 5 x 3 / 4
5 x 3 = 15
15/4 = 3 3/4 or 3.75

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3 years ago
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slava [35]
\displaystyle\int\frac{x^3}{\sqrt{x^2+49}}\,\mathrm dx

Taking x=7\tan\theta gives \mathrm dx=7\sec^2\theta\,\mathrm d\theta, so that the integral becomes

\displaystyle\int\frac{(7\tan\theta)^3}{\sqrt{(7\tan\theta)^2+49}}(7\sec^2\theta)\,\mathrm d\theta
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=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\tan^2\theta+1}}\,\mathrm d\theta
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=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{|\sec\theta|}\,\mathrm d\theta

When \sec\theta>0, we have

=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sec\theta}\,\mathrm d\theta
=\displaystyle7^3\int\tan^3\theta\sec^2\theta\,\mathrm d\theta

and from here we can substitute u=\tan\theta to proceed from here.

Quick note: When we set x=7\tan\theta, we are implicitly enforcing -\dfrac\pi2 just so that the substitution can be undone later via \theta=\tan^{-1}\dfrac x7. But note that over this domain, we automatically guarantee that \sec\theta>0, so the absolute value bars can be dropped immediately.
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