All categories

3 years ago

Today, Jay ran 6 3/4 miles around the track and Nick ran 4 1/2 miles. How many times the length of Nick's was Jay's run?

Mathematics

1 answer:

lord [1]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Help please!!!!!!! and thank you

GarryVolchara [31]

Answer:

2.50000 or 2.5 or 2 1/2

Step-by-step explanation:

You have the number 250,000. you have to get the decimal between 1.00 and 10.00 to do this we are going to move the decimal over left one at a time.

25,000.0

2,500.00

250.000

25.0000 25 is really close but not between 1 and 10 so were going to move the decimal one more time

2.50000

2.50000 is between 1 and 10 so its the anwser we are looking for.

5 0

2 years ago

Read 2 more answers

The table below shows the probability distribution of students in a high school with 1500 students. What is the expected value f

lakkis [162]

D for sure I hope it helps and I know I’m 100% right because I already had this question somewhere else dude so yeah

4 0

2 years ago

Solve by factoring<br> 4x^2=x

Delvig [45]

Answer:

x= 0, 1/2

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the following product?

mixas84 [53]

Question:

What is the following product √30 * √10

2√10

3√10

4√10

10√3

Answer: 10√3

Hope this helps!

7 0

3 years ago

Find the values of the measures shown when each value in the data set increases by 25. Mean: 109 Median: 104 Mode: 96 Range: 45

Vikki [24]

Answer:

The new values are as follows:

Mean: 134

Median: 129

Mode: 121

Range=45

Standard Deviation=3.6

Step-by-step explanation:

When a k real number is added to all the elements of the dataset, the new measures of center (mean, median, and mode) are simply found by adding the value k to the previous values. Thus

$Mean_{new}=Mean_{old}+k$

Here $Mean_{old}$ is 109 and k is 25 thus

$Mean_{new}=Mean_{old}+k\\Mean_{new}=109+25\\Mean_{new}=134$

Similarly

$Median_{new}=Median_{old}+k$

Here $Median_{old}$ is 104 and k is 25 thus

$Median_{new}=Median_{old}+k\\Median_{new}=104+25\\Median_{new}=129$

Also

$Mode_{new}=Mode_{old}+k$

Here $Mode_{old}$ is 96 and k is 25 thus

$Mode_{new}=Mode_{old}+k\\Mode_{new}=96+25\\Mode_{new}=121$

When a k real number is added to all the elements of the dataset, the new measures of variation (range and standard deviation) remain the same thus.

$Range_{new}=Range_{old}\\Range_{new}=45$

Similarly

$Standard\ Deviation_{new}=Standard\ Deviation_{old}\\Standard\ Deviation_{new}=3.6$

So the new values of mean, median, mode, range, and standard deviation are 134, 129, 121, 45, and 3.6 respectively.

4 0

2 years ago