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Julli [10]
2 years ago
10

Omg plz help have no idea question below

Mathematics
1 answer:
Deffense [45]2 years ago
4 0

Answer:

y=3x+1

Step-by-step explanation:

add 3x to both sides of the equation to get it in standard form, then the slope is 3x meaning that you go up 3 units and to the right 1 unit. since our y-intercept is at 1 we start this from there as shown in the images above^

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P and q are two arithmetic sequences. The first four terms of sequence P are 2,6,10,14. The nth term of sequence Q is 145-3n. Th
Tomtit [17]

Answer:

r = 21

Step-by-step explanation:

nth of sequence P :

T_{n} = 4n -2

r^{th} term : 4r-2=145-3r\\4r+3r=145+2\\7r=147\\r=21

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Write three different ways for7/10
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Suppose that, in addition to edge capacities, a flow network has vertex capacities. That is each vertex has a limit l./ on how m
storchak [24]

Answer:

See explanation and answer below.

Step-by-step explanation:

The tranformation

For this case we need to construct G' dividing making a division for each vertex v of G into 3 edges that on this case are v_1, v_2 and l(v).

We assume that the edges from the begin are the incoming edges of v_1 and all the outgoing edges from v are outgoing edges from v_2

We need to construct G' = (V', E') with capacity function a' and we need to satisfy the follwoing:

For every v \in V we create 2 vertices v_1, v_2 \in V'

Now we can add a new edge asscoiated to v_1, v_2 \in E' with the condition a' (v_1,v_2) = l(v)

Now for each edges (u,v)\in E we can create the following edge ( u_r, v_1) \in E' and the capacity is given by: a' (u_r, v_1) = a (u,v)

And for this case we can see this:

|V'| = 2|V|, |E'|= |E| +|V|

Now we assume that x is the flow who belongs to G respect vertex capabilities. We can create a flow function x' who belongs to G' with the following steps:

For every edge (u,v) \in G we can assume that x' (u_r ,v_1) = x(u,v)

Then for each vertex u \in V -t and we can define x\(u_1,u_r) = \sum_{v \in V} x(u,v) and x' (t_1,t_2) = \sum_{v \in V} x(v,t)

And after see that the capacity constraint on this case would be satisfied since for every edge in G' on the form (u_r, u_1) we have a corresponding edge in G because:

u \in V -(s,t) we have that:

x' (u_1, u_r) = \sum_{v \in V} x(u,v) \leq l(u) = a' (u_1, u_r)

x' (t_1,t_2) = \sum_{v \in V} x(v,t) \leq (t) = a' (t_1,t_2)

And with this we have the maximization problem solved.  

We assume that we have K vertices using the max scale algorithm.

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3 years ago
I Will Give You A Brainliest! guarantee
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Answer:

lololol

Step-by-step explanation:

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