Suppose that CA = 12, CB = 20, DF = 6, and FE = 10. Which additional fact would guarantee that the triangles are SIMILAR?
2 answers:
Answer:
It enough to show m∠C = m∠F to guarantee that the triangles are SIMILAR that is Δ ABC ≈ Δ DEF
Step-by-step explanation:
Given : CA = 12, CB = 20, DF = 6, and FE = 10.
We have to find an additional fact that would guarantee that the triangles are SIMILAR that is Δ ABC ≈ Δ DEF
For two triangle to be similar when the ratio of their corresponding sides are same and measure of corresponding angles are equal.
Consider the Δ ABC and Δ DEF
Given CA = 12, CB = 20, DF = 6, and FE = 10.
Consider
Since, ratio of two sides are in same ratio.
Thus, to have two triangles similar it is enough to show that the measure of angle between two sides must be same. by Side-angle-side similarity criterion.
That is m∠C = m∠F
Thus, it enough to show m∠C = m∠F to guarantee that the triangles are SIMILAR that is Δ ABC ≈ Δ DEF
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Answer:
B. 6.3%
Step-by-step explanation:
For each time that the coin is tosse, there are only two possible outcomes. Either it comes up tails, or it does not. The probability of coming up tails on a toss is independent of any other toss. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Fair coin:
Equally as likely to come up heads or tails, so
Probability that the first tails comes up on the 4th flip of the coin?
0 tails during the first three, which is P(X = 0) when n = 3.
Tails in the fourth, with probability 0.5. So
0.0625 * 100 = 6.25%
Rounding to the nearest tenth of a percent, the correct answer is:
B. 6.3%