All categories

3 years ago

A negative correlation between two variables x and y usually yields a negative p-value for r.

Mathematics

1 answer:

Harman [31]3 years ago

6 0

A. True if im wrong sorry hope this helped tho :p

You might be interested in

The base angle of an isosceles triangle measures 54°. What is the measure of its vertex angle?

Elena-2011 [213]

Hope this helps :) If you have a doubt just comment :)

5 0

3 years ago

Read 2 more answers

The line plots show the results of the number of dollars two different age groups of teenagers

kicyunya [14]

Answer:

Step-by-step explanation:

100.9

8 0

3 years ago

EXPERTs/ACE/GENIUS/TRUSTED HELPERs QUICK!!

Pavel [41]

X 0 y was 30

at x 12 y is about 55

12-0 = 12

55-30 = 25

25/12 = 2.08 inches per year average

so answer should be D

5 0

3 years ago

What is the distance between -2 and - 1 1/2

kow [346]

The distance between -2 and -1 1/2 is 1/2:

-2+1/2=-1 1/2
-1 1/2 =-1 1/2
I was trying to show my work but hope this could help you

3 0

3 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago