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Svet_ta [14]
3 years ago
11

Graph ​ y=4/7x−2 ​. Use the line tool and select two points on the line.

Mathematics
1 answer:
Lynna [10]3 years ago
4 0

Answer:

Given equation of the line,

y=\frac{4}{7}x-2

If x = 0,

y=\frac{4}{7}(0) - 2=0-2=-2

Thus, the line intercepts y-axis at (0,-2)

If y = 0,

0=\frac{4}{7}x-2\implies 2=\frac{4}{7}x\implies x=\frac{14}{4}=3.5

Thus, the line intercepts x-axis at (3.5,0)

By joining these two points in the graph,

We will get the graph of the given line ( shown below )

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Natasha2012 [34]
The answer is 0.50.

P(4<=X<=8)=P(x=4)+ P(x=5)+ P(x=6)+ P(x=7)+ P(x=8)= 0.05+ 0.15+0.15+0.15 +0 = 0.50

Notice that in 8 the line touches the x axis so it’s corresponding probability is 0.
5 0
2 years ago
Easy question easy points
Deffense [45]

Answer:

y = - 4x - 8

Step-by-step explanation:

From the graph we get :

slope = (-8)/2 = -4

y-intercept = -8

8 0
4 years ago
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Solve the inequality: x/-3 &lt; -10
seropon [69]

Answer:

x>30

Step-by-step explanation:

x/-3<-10

x<-10*-3

x<30

x>30

8 0
3 years ago
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Please solve the problem ​
jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.

Then you can eliminate <em>Y</em> by taking the sum

4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>

==>   <em>X</em> = (4<em>A</em> + <em>B</em>)/11

Similarly, you can eliminate <em>X</em> by using

-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>

==>   <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11

It follows that

X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}

Similarly, you would find

Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}

You can solve the second system in the same fashion. You would end up with

P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}

3 0
3 years ago
Which of the following statements is not true
AveGali [126]
C is false because 30 is both divisible by 5 (30/5=6) and 10 (30/10=3) and is also divisible by 6 since 6*5 is 30
4 0
4 years ago
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