2 years ago

Evaluate expression: evaluate each expression when a = "-2" b=4 and c=-10

Mathematics

1 answer:

densk [106]2 years ago

3 0

Answer:

2a+b=0

ac-b=16

a+b/a=-4

8a+5b=-4

-4a-b =4

3c/-5=6

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Help please!!!!!!!!!!!!!

KatRina [158]

Hello!

For this you can plug in the x values in the choices and see if you get the y value

y = $-4^{3} - (-4)$

-4^3 is -64

when you subtract a negative you are just adding

-64 + 4 = 60

Then you do the second one

$y = -3^{3} - (-3)$

-3^3 is -27

-27 + 3 is -24

Then the third one

$y = -2^{3} - (-2)$

-2^3 is -8

-8 + 2 is -6

Then the last one

$y = -1^{3} - (-1)$

-1^3 is -1

-1 + 1 = 0

Since we did not get -2 the answer is D

Hope this Helps!

7 0

3 years ago

Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$