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4 years ago

Find the slope of a line parallel to the given line.

Mathematics

1 answer:

Ede4ka [16]4 years ago

4 0

The slope would be the same as the equation. So 8/5 is your answer

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-Question Worth 20 points!!-

Nastasia [14]

Answer:

A. 9

Step-by-step explanation:

A counterexample shows that one side is true while the other is false

x>7 and x>11

sub in the answers

9>7 and 9>11 -this is true for the first half but false for the second

5>7 and 5>11 -this is false for both

13>7 and 13>11 -this is true for both

15>7 and 15>11 -this is true for both

Answer A is correct as it proves the statement to be incorrect

7 0

3 years ago

1. 4x=3y+3, 6y= 8x+ 36.

GaryK [48]

4x=3y+3 and 6y= 8x+ 36 and y=3x-1 and y= 6- x/3

4x=3y+3 and 6y= 8x are parallel and y=3x-1 and y= 6- x/3 are perpendicular.

See the attached plot for answer.

7 0

4 years ago

Solve - pv + 40 < 65 for v<br> solve 7w - 3r = 15 for r

Katarina [22]

Answer:

v > -25/p

r = -5 +7/3 w

Step-by-step explanation:

- pv + 40 < 65

Subtract 40 from each side

- pv + 40-40 < 65-40

-pv < 25

Divide each side by -p (remember to flip the inequality since we are dividing by a negative)

-pv/-p > 25/-p

v > -25/p

7w - 3r = 15

Subtract 7w from each side

7w-7w - 3r = 15-7w

-3r = 15-7w

Divide by -3

-3r/-3 = (15-7w)/-3

r = -5 +7/3 w

8 0

4 years ago

What is the least common denominator for fractions that have denominators of 5x+10 and 25x^2-100

s344n2d4d5 [400]

What is the least common denominator for fractions that have denominators of 5x+10 and 25x^2-100

6 0

4 years ago

Solving 8 problems per minute, Fast Finn can finish his test in time. He was however, working faster, solving 10 problems per mi

mrs_skeptik [129]

Answer:

Number of problems = 240

Step-by-step explanation:

Let x be the number of questions and t be the time.

Given:

Average rate = 8 problems per minute

Fast Finn rate = 10 problems per minute

Fast Finn taken time = t - 6

We need to find the number of problems on the test paper.

Solution:

Average rate to solve test paper.

$Average\ rate =\frac{Number\ of\ questions}{time}$

$8 =\frac{x}{t}$

$t =\frac{x}{8}$ --------------(1)

Fast Finn rate to solve the test paper.

$Average\ rate =\frac{Number\ of\ questions}{time}$

$10 =\frac{x}{t-6}$

Using cross multiplication rule.

$x=10(t-6)$

$x=10t-60$

substitute $t =\frac{x}{8}$ from equation 1.

$x=10(\frac{x}{8}) -60$

Rearrange the equation as:

$x - \frac{5}{4}x = -60$

$\frac{4x-5x}{4}=-60$

$-\frac{x}{4} = -60$

Using cross multiplication rule.

$x = 60\times 4$

x = 240 problems.

Therefore, 240 problems were on the test.

4 0

4 years ago